ACCT1501/1511
Financial Accounting - An Integrated Approach (3rd edition) and Management Accounting Supplement (2nd edition) by Ken Trotman and Michael Gibbins
both in excellent/perfect condition. the management accounting supplement is contacted. note: these are older editions of the...
according to unsw handbook it is a prerequisite.
(see UNSW Handbook Course - Actuarial Studies and Commerce - ACTL1001)
maybe check if it's not too late to switch enrolment from econ1203 to math1151?
dvse - just wondering, did you attempt this while you were at uni (i.e doing investments in addition to a full load of uni subjects)? I've been getting mixed messages from friends who have received advice from colleagues at work regarding this.
For com/sci students it would be discrete maths (i think its math1081?)
For straight commerce it depends on your co-major/minor. If finance, then FINS1612
From past experience, we don't really care about your subjects. It's more about what you write on your application form.
Apparently one of the scholars from my year was able to get a phone/webcam interview as he lives in Darwin.
Yes.
At that point you won't have any of your marks or...
16 Actuarial Studies Co-op Scholars were chosen in 2006, 17 in 2007 and I think 13 in 2008, so yeah, about 15.
It depends on how many companies are willing to sponsor us.
As stated above, it depends on whether current co-ops get kicked out, or new sponsors join the program. Don't count on it - your best chance is getting in as a first year co-op.
Correction:
http://community.boredofstudies.org/136/faculty-commerce/35469/actuarial-exemptions/3.html
As Affinity mentioned above, you can still get in if a current scholar is kicked out due to not making the credit average, or simply decides to leave.
Another possibility is that a new sponsor company may sign-up part-way through your degree, in which case there will be another place available.
Hey there. Good effort with the solutions =)
I actually tried the paper today because I wanted to see what the fuss was all about. It's quite straightforward if you know what you're doing, although a little rushed.
For the most part I agree with what you've done, although I think there...
hold on a second; i just thought of something
since z1 -iz2 -z3 + iz4 = 0
therefore (z1 - z3) = i(z2-z4)
we all agree that the diagonals are perpendicular. and from the other condition, that opposite sides are equal.
but, rotation by i does not affect the length of a vector...