Recent content by WeiWeiMan

probably a,b,c > 0 and a≠b≠c since this looks like an application of AM/HM rearranged a bit consider (a+b+c)(1/a+1/b+1/c) > 9 (a+b)(1/a + 1/b) > 4

cloudy

You can't add days to your life, but you can add life to your days.

do you happen to also be 6'6

school tryna sabotage you fr

roughly 35-40

if you've covered everything, you probably don't learn any content after trials you may learn some heuristics/exam technique tho

a. 9 choices for first digit (can't be 0), 9,8,7 etc for next digits total = 9*9*8*7*6*5*4*3*2*1=9*9! = 3265920 b. 9 choices for first digit (can't be 0), 10 for each subsequent digit total = 9 * 10^9 [9 other digits]

perms and combs is very difficult

:awesome:

how much you good with $300 per exam?

.95 inc

still are

nah i'd win