Recent content by sasha279

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    Correct Multiple Choice Answers (checked by teacher)

    Let me know: 1 A 2 B 3 D 4 A 5 B 6 C 7 D 8 A 9 D 10 C 11 D 12 C 13 A 14 C 15 D 16 B 17 B 18 A 19 C 20 B
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    Booklets

    I got 4 x 8 page booklets... Heh heh heh I third that
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    So, who noticed the two mistakes on page 18?

    Yeah I got #2. I'm like... wtf!! But for #1... How did you attempt that question? How did you solve it? Sash
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    Q12

    C, I felt that the system requirements should only be decided _after_ feedback is gained from users regarding their opinions. System requirements includes the purpose anyway... ?
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    lol DSS question

    Yeah I was just like "it might have an impact on the people assessed by the system as it might affect their self-confidence or they may become dependant on the system for assessing the beauty of people's faces." Come on, that was a philosophy question, not damn IPT :P
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    Multiple Choice Answers (checked by teacher)

    Here are the 'proper' solutions (not checked by BOS): 1. A 2. D 3. A 4. D 5. A 6. B 7. B 8. C 9. D 10. B 11. C 12. C 13. D 14. C 15. B 16. A 17. C 18. C 19. B 20. B I would scan in a copy of my paper but I've scribbled notes all over it ^_^;
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    How many booklets did you use

    Same.
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    Can someone post the questions up?

    If anyone's teacher/etc has a copy of the paper...
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    not sure is i got these right. plz halp.

    Posting the questions might help??
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    Q10a

    Do you mean x = e^y + 2? Yup I also got 5ln5 - 4 ^^
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    How far below the x-axis is the beam when x=0?

    How did you find C? I let f(b) = f(-b) but it didn't work... Got C = C hehe ^_^;
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    Easy Question 10 or Easiest?

    Hehe, one of my friends forgot to put proofs in the geometry question! That's a bit of a worry hey ;)
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    Easy Question 10 or Easiest?

    V = pi x integral(x^2dy or y^2dx)
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    Easy Question 10 or Easiest?

    I did that but my answer for part (ii) didn't look like theirs? It was very different and I spend pages and pages trying to factorise it, but it never matched... I said the total area is A = 1/2.s.x.sina + 1/2.(l-x).s(l-x)/x and I think I'll get some marks for that but... I just...
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