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You just make it accute with the verticle velocity negative...

They are all talking about how the performance of 4 unit pple in the 3 unit exams affects our 4 unit scaling. So post ur 3 unit marks....83

Why are u talking about this? Maths is over, let the board worry about this stuff...there's not much more u can do :)

It's not that I dont respect the solns already up there, but can someone put up solns from a respected author, like happened in mx2 with lee...

Negative angles...mate all u did was make y^. negative because it was falling, not the angles...

Keypad...we all know what happened in 2003, can u seriously get over HSC maths and stop visitng forums 2 years after saying how good u were back then...seriously get a life.

It doesnt matter man...1 mark is for working, one is for the answer...be happy u got it :D

That comments sickens me...they maintain typical arrogance even when they havent finished...Mr Yang, obviously if it wasn't hard then you would have finished it...

Personally I am pleased with the standard of both tests...though both question 7 and 8 were too easy for HSC exams, but they've done well. Im thinking 67-69 for band E4 in my opinion...

Dont embarrase urself by correcting me... I was talking about the chain rule in the differentiation of the thing to be integrated...

Omg dude dont be soo ignorant...I want u to find d/dx (sinx)^3...its called chain rule u learnt in 2 unit...there was no bias, so dont be bitchy :D

I got 83 for 3 unit and 107 for 4 unit... 77 is like 97 which is good man :D

same man...except I think I made one silly...damn u gonna beat me for top place Why is everyone complaining about 4 unit...it was pretty basic with a ezy question 8...

I got 83 - 1 silly...lol costs top place :(

Is there any terry lee or co solns for this paper...like there is for ex 2...??

yes u will...

Pretty sure i got 83/82...had about 20 mins to check it...no dramas...except q7 (a) i was stuck on..but it was aight.

Lol...people chain rule like d/dx: (2x^2-1)^2 = 2 (2x^2-1).4x

sorry my internet has been down...I dont really know how 2 explain it apart from what I've been saying...what bit are u unsure about? And stefano what was that link: i dont get it? Edit: you dont need the length of the hypotenuse... the 2 sides are h and 5 and the perpindicular height is found...

K at x=h draw a horizontal line going 2 the deep end. Then use pythagoras on the top triangle to work out perpendicular heights...comes out at 5h for me...fuck i need 2 put my diagram up but i cant seriously...its like a trap face with depth = 5 on left and depth = 1 on right...