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1. ### UNSW chit chat thread

Re: UNSW chit chat thread 2016 Define "good".
2. ### First Year Mathematics B (Integration, Series, Discrete Maths & Modelling)

Re: MATH1231/1241/1251 SOS Thread Woops, I did a mistake in dimension and thought that Ax is still 3x5 matrix
3. ### First Year Mathematics B (Integration, Series, Discrete Maths & Modelling)

Re: MATH1231/1241/1251 SOS Thread Is there missing detail like Ax = 0 or Ax is an element of ___
4. ### UNSW chit chat thread

Re: UNSW chit chat thread 2016 It's a message
5. ### MATH1081 Discrete Maths

Re: Discrete Maths Sem 2 2016 Another method: if gcd(a, b) = d, then by Bézout's identity, there exists integers x and y such that ax + by = d. Dividing through by d yields (a/d)x + (b/d)y = 1 because d cannot be 0. Then reverse Bézout's identity to conclude that gcd(a/d, b/d) = 1.

Yes

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8. ### MATH1251 Questions HELP

$Let$I = \int_0^1 x^m (1-x)^n dx $and keep integrating by parts to reduce$x^m$down to$x^0$,$ \\ \begin{align*} I &= \left[ -\frac{x^n(1-x)^{n+1}}{n+1} \right]_0^1 + \frac{m}{n+1} \int_0^1 x^{m-1}(1-x)^{n+1} dx \\&= \frac{m}{n+\color{red}{1}}\int_0^1...
9. ### Cambridge HSC MX1 Textbook Marathon/Q&A

Re: Year 12 Mathematics 3 Unit Cambridge Question & Answer Thread (1+x)^{n-1} = \binom{n-1}{0} + \binom{n-1}{1}x + \dots + \binom{n-1}{n-2} x^{n-2} + \binom{n-1}{n-1}x^{n-1} \\ $Put$x = 1, \\\\ 2^{n-1} = \binom{n-1}{0} + \underbrace{\binom{n-1}{1} + \dots + \binom{n-1}{n-2}}_{\text{isolate...

Sorry, I don't know this one. I forgot nearly all of this but try going through each step of the experiment and see if you can spot any inconsistencies that arise

Sure

Yeh, don't do that. Pb(NO3)2 and PbSO4 were in 3:3 ratio. Doing that puts it in 3:9 ratio

yeh

Sorry, I misunderstood what you were saying. Pb(NO3)2 and PbSO4 coincidently have a mole ratio of 3:3, so 1:1. This does not mean you should always use the moles of a reactant (which supposedly has same mole ratio to the desired product) to find the moles of a product because it may be in...

Did you mean 0.085?

That's finding the number of moles of Al2(SO4)3 and you cannot use this to find the moles of PbSO4 because it's the excess. You must use the limiting reagent to find the moles of PbSO4