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With reference to MX2, the new syllabus has been dumbed down somewhat with the introduction of some new topics. In the IB Maths HL (i.e. International Baccalaureate Maths Higher Level) syllabus, vectors are covered in greater depth. This includes: scalar product, vector product, vector eqn of a...

I also do the HSC syllabus, of course, including the new one. The newer parts of the new HSC have been in the IB Maths (SL & HL) courses for more than 2 decades. The IB HL in fact cover Vectors to a greater depth than the new HSC Maths Ext 2. I do 1-on-1 and small groups. I can now do this...

Q2 Very heavy LaTeX typing! I'll skip the many little steps that you can easily do yourself. a) OK - you can show true for n=1. Let formula hold for n = k >=1 $i.e. $ x_n = 2 \left ( \frac {1+\alpha ^k}{1 - \alpha ^k} \right ) \\ \\ \therefore x_{n+1} = \frac {4 + 2(\frac {1+\alpha...

As fan96 has pointed out, I'm amazed you are doing the questions that way. Luckily for you, you now have feedback on your own effort. Try to improve your approach.

buMp I also tutor HSC - and Prelim: both the old and the new syllabuses.

buMp

Bump

Do this, if you can handle MX2. Whilst religion may be important and/or interesting to many people, you don't have to pursue it as an HSC subject.

bUMP

Do you think pc would still be hanging around Bored?

With students taking their final exams later this year, I'm ready to accept a few more students. Remember - don't leave it too late.

This is a Binomial Probability question. \binom 8 3 p^3 (1-p)^5 = 4 \times \binom 8 2 p^2(1-p)^6 Solving you get the P(even) in a single throw = p = 2/3.

Let cost price = C and original marked price = P .: discounted selling price = 0.8 P = 1.1 C .: P = 1.1/0.8 C = 1.375 C .: original percentage profit = 0.375 x 100% = 37.5%

iv) 3 seconds. Above the given height from t = 1 sec to t = 4 sec.

a) since <BXC is 90 deg, B, X, C lie on semi-circle, diameter BC, centre M. .: BM = MC = MX, being radii of this semi-circle. b) since BM = MX, MBX is an isosceles triangle. So base angles MBX and MXB are equal = @ say. c) .: <DAC = <DBC = @ and < CXM = 90 - < MXB = 90 - @...

Just Do It. Although you go to a low-ranked school, you are obviously good in maths.

If you self-study in yr 7, you train yourself in self-reliance. If you are able to cope well in your Yr 7 this way, then continue with the next year and the next year until, and if, you find the going hard without additional help. Give it a try.

Why don't you just self-study and use the money saved for your tutoring in Yr 10, 11 and 12. Yr 7 is nuthin.

One of the end-points of the chord has x = 8, one of the 2 solutions of the quadratic eqn; so Q corresponds to the other solution x = 2.