Search results

Oh yea, I'm bad with domain/range of inverse trig :( I know the domain is the original function's range, but I still get confused :bomb:

lol really? such as?

This is just a matter of opinion. Mine would have to be projectile motion, but I haven't started any probability or mathematical induction. Also, any tips would be appreciated :)

^yeah what he said. Even if you stuck with your working sinx=0 cannot be a solution as cotx would become undefined

Multiply by e^{4x} e^{4x}y=cos3x \\ e^{4x}\left (\frac{dy}{dx} + 4y\right ) = -3sin3x \\ e^{4x}\left (\frac{d^{2}y}{dx^{2}} + 4\frac{dy}{dx} \right) + 4e^{4x}\left (\frac{dy}{dx} + 4y\right ) = -9cos3x Multiplying by e^{-4x} \frac{d^{2}y}{dx^{2}} + 8\frac{dy}{dx} +16y =-9y \\...

I wish I had read this before it was in my exam today -____-

I see, but it does make some questions easier e.g. $If $ y=e^{-4x}cos3x,$ prove:$ \\ \frac{d^{2}y}{dx^{2}} + 8\frac{dy}{dx} +25y = 0

Thanks, I just learnt implicit differentiation today, not sure why us 3U students aren't taught it though it comes in handy.

It should be stressed that you should learn the concepts if you want to do well, not just the methods. The HSC can throw anything at you, so if you just learn how to do certain questions you won't understand what's actually happening.

Copying text is much different to writing from memory

log_{e}e^{(3y-1)} = (3y-1)log_{e}e = 3y -1 \\ \text{since lne = 1}

3U maths, I hate english more than anything

How do I get LaTeX?

How do you get from the 2nd to 3rd line?

smh

1. The two triangles are congruent (top angles are the same, PS is common and PSQ=PSR=90, or equiangular) Thus through pythogoras' theorom PS^2 = PQ^2 - SQ^2. But SQ = RS and PQ = PR (as they are congruent) Therefore PS^2 = PQ x OE -RS x SQ I'm at tafe right now hence I can't use the proper...

If you fill out a valid illness/misadventure form, they cannot give you a zero.

Fucking repped.

Duh..

*opens new tab*