Re: Summer '08-09 Chatter Thread
ok now, when i click on get a new timetable, i get the same one i edited for the times.
??
this is soo confusing =[
ill post up the timetable and you will see what i mean .
Re: Summer '08-09 Chatter Thread
yeh cosmic that was i meant, soooo basically if i get my final timetable with the blue highlighted thing on the times ive chosen that has subject in them, it cant be changed ok thanks..
Re: Summer '08-09 Chatter Thread
huh ??
this is what i can after i clcked on "get me a similar timetable "
i got my normal but then on the time i selected yes its blue but the subjects are still there ???
what does that mena
Re: Summer '08-09 Chatter Thread
guys when your subjected is highlighted when you use the option take up to 5 hours off on the following two days, where do they go because i seriosuly dont know where they wetn ??????????????????????
HELPPPPPP
hey majoirty of the timetables in usyd are allocated by the uni/faculty it self.
you can only choose to take ONE day off, OR take up 2 5 hours on two days.
You can pick individuals classes as most say. =[
I can see why its not worth anything, is it only for people who want more knowledge and hwo clear is it that people who do arts get no job when they graudate.
I see the subjects are just not employable.
SEX
Hey there guys, Im looking for anyone with 1st year Education books, if any of you young lads might know anyone can you send it through this way thanks =]
im bore dude, cant you see on my account it says " must be avoided" if you followed it you would of got it.. sorry im just bored...
ok here is a good one =]
Well I know many of you might not know this, but it seems pretty helpful and I wish i knew this b4 the hsc =]
so anyways when you are thrown at some retarded question saying find mod and argument
no matter how ugly it gets you calculator will find it =]
we know that if z=x+iy
then mod=...
The question was find S e^(1+i)x dx
using the fact e^iy = cosy+isiny
therefore
e^x+ix = e^x * e^ix = e^x(cosx+isinx)
therefore S e^xcosx +ie^xsinx = Se^(1+i)x
Using integration by parts on the expanded version
S e^xcosx dx = e^x/2 (cosx+sinx)
and S e^xisinx dx = ie^x/2...
I got it =]
simple sign mistake
€
can some one confirm this solution please.
is it
e^x/2 (cosx+sinx) + ie^x/2(sinx-cosx) = e^x/2( cosx+sinx +i(sinx-cosx) ) + C ???