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ITS GUO EN SHAO

Not that bad actually. Square both sides and you come to the conclusion that: xu+vy=0 . z/w the real part is (xu+yv)/(v^2+u^2) and that's 0 hence purely im

Does my Binomial expansion not work, cus that and Induction is the only way My small brain can think off. was thinking of complex numbers too since its in that form but yeah haha

Someoen put insanely difficult proof question uwu

Use Binomials to expand (M+1/M)^n?

Chapter 7-11 u can do it in 5 days brudda

Im dumb, i can type set as u can see haha. I meant: "and the angle bisector as \vec{c} \cdot \vec{b} = |\vec{c}| |\vec{b}| \cos \theta" So sorry did it in a hurry, but the maths should be write afterwards

Oh i just wanted to reach the conclusion with the last paragraph quickly. I constructed that vector as an arbitrary vector that will act as a bisector. Didnt want to use the fact that its half a rhombus and in essence that is the way the complex method I was referring to would've been...

a-b is the base... That proof i did was fine, I did state they were position vectors. And if u can assume its a median why not just use properties of rhombus and use complex like CM_Tutor, you will just get it out instantly then lol

Let the position vectors be \vec{a} and \vec{b} where |\vec{a}|=| \vec{b}| and the ancle bisector as \vec{c} \cdot \vec{b} = |\vec{a}| |\vec{b}| \cos \theta This stands that, \vec{a} \cdot \vec{c} = |\vec{a}| |\vec{c}| \cos \theta also that: \vec{b} \cdot \vec{c} = |\vec{c}|...

oh no i just wanted to show theres another way of doing the qtn and didnt provide a sketch cus too lazy. Since Ik that its nice values and all used amgm, but, i would sketch during exam if i were to use it

Assuming that x and y are positive integral values in the real field. We can quote the AM-GM inequality and solve it as: \frac{x+y}{2} \geq \sqrt{xy} \rightarrow xy \leq 14^2 \text{Factors are <4,49> and <14,14>, but remember it has to add to give 28 so <14,14> is the only viable tuple} EDIT...

Yo, even if you dont prefer your teacher, or even if they got the syllabus wrong, no need to flame them. Bruh everyone makes mistakes, and yeah you did the right thing by comparing here, but dont flame them!

The enemy of the enemy of the people are the friends

I actually have another elegant proof, but this comment box is too short to contain it.

Chitoge best girl fight me

@Etho_x x.x i was watching nisekoi at that time. jkjk WIsh u all the best. HSC for me is next year ripppp

damn theres a 2021 hsc chat x.x

Damn i didnt see the 1/6th of rectangular prism x.x . Went straight for volumes by slices ahahha. For b) Recognise it is a rectangle, use combination approach to solve it. I am getting 756756 is that correct?