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  1. K

    Who did well in UMAT? HOW?

    2008: S1:47 S2:59 S3:57 Overall score:163 Percentile: 72% 2009: S1: 69 S2: 58 S3: 67 Overall score: 194 Percentile: 98% Last year I was quiet lazy and wasn't fully committed to a career in medicine. I was already planning to take a year off so I didn't prepare at all expect for the ACER...
  2. K

    2009 UMAT Official Results (No Spam)

    Improved a heap compared to last year. 2008: S1:47 S2:59 S3:57 Overall score:54 (total 163) Percentile: 72% 2009: S1: 69 S2: 58 S3: 67 Overall score: 65 (total 194) Percentile: 98%
  3. K

    Dux

    Haha. I got my name on a board(who cares about that!) and a scholarship (which I wont be using). I wish they had given me a nice book!
  4. K

    ALL NIGHTERS ON TUESDAY thread

    Of course they come out at 530 for you. :)
  5. K

    ALL NIGHTERS ON TUESDAY thread

    All the talk about times they have come out early, is just making this last 15 minutes much longer than it needs to be.
  6. K

    ALL NIGHTERS ON TUESDAY thread

    Sorry if its been asked/replied, whatever. Using the SMS way, we only get a HSC mark, not an internal scaled assessment mark and our external mark. How do we get that? Website?
  7. K

    Results countdown

    LOL I had a dream where i got 52 in english advanced as well! That's pretty insane we both dreamt we got 52. Don't get so hung up on getting first in the state. If you think you have a chance, then I am betting you went really well anyway!
  8. K

    Biased Marking

    ... maybe ... they ... use ... scissors? So it doesn't matter! YAY o.O
  9. K

    Section I: Multiple Choice

    Well if you remember tests on the most reactive group 1 metals, they all bounced across the water burning. Which is what Q is described as doing, so clearly its the most reactive. The highest voltage would come from a really reactive metal with an unreactive one. So R is described as being...
  10. K

    Thoughts?

    Ahhhhhh I forgot to times by 2!! How could I forget that. I haven't got a moles questions wrong since like day 1. Pretty funny actually. Anyone know what the question was out of? 2? Meh, they better carry errors in chem lol.
  11. K

    Section I: Multiple Choice

    Haha woops, did it wrong. Ill edit
  12. K

    Section I: Short Answers

    Possibly, I think if you look at your potentials sheet chlorine gas is more easily reduced than aqueous chlorine. Also, why would they put the chlorine gas there? They don't usually try and trick people in such a way.
  13. K

    Section I: Multiple Choice

    The sample at Site 1 is just after the sewage plant discharge, this would increase the BOD and E. Coli, for obvious reasons. This would disperse by the Estuary sample. EDIT: The TDS at site 3 is very high, this would be because of the salty water of the sea, compared to the fresh water...
  14. K

    Section I: Short Answers

    Never really read anything that said some didn't cross over. I was vague in my answer by not specifying which beaker, so hopefully... Yeh, I knew they occured there, just never learnt what chemicals took part in those buffers. I guessed it was CH3COO- + H2O --> CH3COOH + OH- ?? And...
  15. K

    Section I: Multiple Choice

    >.< how can you argue when I just did all the working? Its a very small amount, so even if there arn't many moles in it. The amount of H+ per volume is high. The pH of the HCL alone is 1.1 1 ph higher corresponds to a 10 times lower concentration of H+. so 1.1 to 2.7 is nearly 100...
  16. K

    EST HSC Exam

    nah i didn't do 1200m. I got that part right, calculated for 45v. Just forgot to divide by two. It was more of a sarcastic "there were two wires? :(" like, DUH. Didn't study much for engo anyways, 1 hour max since I finished school. other subjects have far better scaling.
  17. K

    Section I: Multiple Choice

    Thats moles. Ph = -log10[H+] c = n/v volume is 20mls +30 mls = 0.05 L therefore [H+] is 0.0001/0.05 = 0.002 Ph = -log10[0.002] is equal to 2.69... = 2.7
  18. K

    Multiple choice-Q14

    n(H+ in HCl)= 0.02 x 0.08 = 1.6x10^-3 n(OH- in NaOH)= 0.03 x 0.05 = 1.5x10^-3 That is right But 0.0016 - 0.0015 is 0.0001 This is number of moles of H+ ions left in the solutions Ph = -log10[H+] c = n/v volume is 20mls +30 mls = 0.05 L therefore [H+] is 0.0001/0.05 =...
  19. K

    Section I: Short Answers

    True.. but which ions? Hm, yeh the catchment was a bit different. I forgot completly what a buffer in nature was. So i said "assuming acetic acid is a buffer in nature". What did everyone get for the basic, acidic, neutral salts?? Also what equation did you use for one of the basic...
  20. K

    Section I: Multiple Choice

    Left <> right Reactants <> products adding more reactants, means that more products must be formed to counteract the change. Ie as the question asks for, a shift to the right. 15/15 for me. Somehow!
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