# Easiest Paper Ever (1 Viewer)

#### Bliske

##### New Member
(Assuming you're talking about Question 30 (b) (ii)) How did people get 61? (Caveat, I don't do General Maths though, so I might have missed something.) Note that 1 byte = 8 bit. So 3072 MB = 3072 megabyte = 3072*8 mb (megabit).

Therefore, the speed in megabit per second required (noting 7 min. = 420 s) is

(3072*8 mb)/(420 s) = 58.51429... mbps, which is 59 to the nearest whole number.
Your correct in saying 1 byte = 8 bit. However, 3072 Megabytes must first be converted to bits, so that then we can find the amount of Megabits. So, 3072 MB = 3072 megabyte = 3072*8 mb (megabit), is not true.

The correct working is:

3072 MB (Megabytes) * 1024 *1024 * 8 = 2.576980378x10^10 b (bits).

2.576980378x10^10 bits/1000x1000 = 25769.80378 mb (Megabits)

Therefore, 25769.80378/Mbps = 420

Rearranging this gives us 61.356675.....Mbps

Which is 61 Mbps to nearest Mbps.

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• InteGrand

#### BigBusty

##### New Member
2^20 x 8 x 3072 / 1 000 000 =25769.80378
25769.80378 / 420 = 61.35667566

60 x 7 = 420 seconds

#### InteGrand

##### Well-Known Member
3072 MB (Megabytes) * 1024 *1024 * 8 = 2.576980378x10^10 b (bits).

2.576980378x10^10 bits/1000x1000 = 25769.80378 mb (Megabits)

Therefore, 25769.80378/Mbps = 420

Rearranging this gives us 61.356675.....Mbps

Which is 61 Mbps to nearest Mbps.
Yeah thought so: in other words (assuming this is the case), the thing I missed is that the "mega" in megabits is 1000^2, whereas in megabytes it's 1024^2 (I was assuming "mega" referred to the same factor in both cases).

Looking briefly at Wikipedia, there seems to be some ambiguity about whether it refers to 1024^2 or 1000^2 (e.g. see https://en.wikipedia.org/wiki/Megabyte ). But there's probably a convention that's used in General Maths, so as long as that was used, you'll be correct.

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#### BigBusty

##### New Member
Hope that's right ahha

#### Bliske

##### New Member
Yeah thought so: in other words (assuming this is the case), the thing I missed is that the "mega" in megabits is 1000^2, whereas in megabytes it's 1024^2 (I was assuming "mega" referred to the same factor in both cases).

Looking briefly at Wikipedia, there seems to be some ambiguity about whether it refers to 1024^2 or 1000^2 (e.g. see https://en.wikipedia.org/wiki/Megabyte ). But there's probably a convention that's used in General Maths, so as long as that was used, you'll be correct.
Agreed, it is quite ambiguous. For example, I'm quite sure for instance that beyond the general maths syllabus 1 Megabyte = 1000 Kilobytes, however the general maths convention is that 1 Megabyte = 1024 Kilobytes.

#### BigBusty

##### New Member
For question 15 was it C?

#### BandSixFix

##### Disillusioned
If it was so easy then rip scaling LOL

#### InteGrand

##### Well-Known Member
For question 15 was it C?
Entirely depends on what "part thereof" meant. It seems to me it should just mean you get charged 54 cents for each 30 second chunk, as long as you enter a 30 second chunk (but again, I don't do General Maths. But this is what I thought 'part thereof' meant from general knowledge.). So something like 33 seconds would count as two chunks (so 108 cents charged). If this is the case (a quick Google search appears to suggest it is), then answer is (D).

If however, it just means 54 cents per 30 seconds (namely, the cost for a time t seconds is 54*(t/30) cents), then (C) is the answer.

It seems like General Maths papers' Q's are sometimes potentially ambiguously worded (or at least, ambiguous for someone who didn't do the course. Maybe all these phrases have conventions as to how they are to be interpreted in General Maths. E.g. maybe the definition of "part thereof" is explicitly taught so that no-one would be confused.).

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#### Bliske

##### New Member
If it was so easy then rip scaling LOL

I don't think it was an easy test. The last two years tests (especially 2015 paper) were much easier imo. Their were a lot more mathematically orientated questions this year, which I think benefited those who have an intuitive mind, which is why I think some people found it easier, but I'm sure for the majority of the state it would have been much difficult than previous years (seriously the 2015 paper was more simpler compared to this year).

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#### Bliske

##### New Member
Entirely depends on what "part thereof" meant. It seems to me it should just mean you get charged 54 cents for each 30 second chunk, as long as you enter a 30 second chunk (but again, I don't do General Maths. But this is what I thought 'part thereof' meant from general knowledge.). So something like 33 seconds would count as two chunks (so 108 cents charged). If this is the case (a quick Google search appears to suggest it is), then answer is (D).

If however, it just means 54 cents per 30 seconds (namely, the cost for a time t seconds is 54*(t/30) cents), then (C) is the answer.

It seems like General Maths papers' Q's are sometimes potentially ambiguously worded (or at least, ambiguous for someone who didn't do the course. Maybe all these phrases have conventions as to how they are to be interpreted in General Maths. E.g. maybe the definition of "part thereof" is explicitly taught so that no-one would be confused.)
This basically summarises general maths. Ambiguously worded questions.

Your correct in your assumption of "part thereof". It does mean in 'blocks' - e.g. 34 seconds is 2 parts (or 'blocks') thereof. So D is correct if you have worked out the question in 'blocks'.

#### BigBusty

##### New Member
What mark would be a state rank for this exam?

#### Bliske

##### New Member
What mark would be a state rank for this exam?
I'm predicting 98-99+. You never know, it could be higher or lower.

#### BigBusty

##### New Member
Hey guys for the 5 marker are we sure we had to add the triangle since it does not specifically mention the triangle in the question?

#### Bliske

##### New Member
Hey guys for the 5 marker are we sure we had to add the triangle since it does not specifically mention the triangle in the question?
If you look at the wording of the question it states "a school playground consists of a part of a circle, and a rectangle." Hence, the area of the playground does not include the triangle. This is how I interpreted it at least. It will be interesting to see if the triangle was meant to be included.

Also, why was this a five mark question? Their was only three steps required to solve it, and it wasn't too difficult in terms of figuring out how to find the answer.

#### whatarethoose

##### Member
look at the black outlining of the shape? why wouldnt you include the triangle?

#### Bliske

##### New Member
look at the black outlining of the shape? why wouldnt you include the triangle?
Because the question explicitly asked you to find the area of the playground which "consists of a part of a circle, and a rectangle" (taken directly from the question). I think this clearly suggests that you were not meant to include the triangle. Further to this, the dotted lines around the triangle may somewhat hint that you were not meant to include the triangle. Also, this was one of the last questions, which often entail 'wordy' questions designed to trick indivduals who do not have a discerning eye.

I could be wrong I guess. The mark allocation would make a little bit more sense if you had to include area of triangle. But, I still uphold that the triangle was not meant to be included.

Edit: Now that I think of it, the "part of the circle" includes the triangle because the part of circle includes the triangle because the part that is chopped of is the top of the circle (if that makes sense). What a dumb question.

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