a) My answer: Potential difference is positive so ΔV = ΔU/q

and since potential difference is positive so must be ΔU.

ΔU = q*ΔV = (-1.602 * 10^-19)(100)

= -1.602 * 10^-17

ΔU = -ΔKe

-1.602 * 10^-17 = -ΔKe

1.602 * 10^-17 = ΔKe

**½mv^2 (f) -**

½mv^2 (f) =

**½mv^2 (i) = 1.602 * 10^-17**½mv^2 (f) =

**1.602 * 10^-17**then re-arranging for v and solving the values I got:

v = 1..86 * 10^7 m/s

b)

ΔU = q*ΔV = (-1.602 * 10^-19)(100)

= 1.602 * 10^-17

ΔU = -ΔKe

-1.602 * 10^-17 = -ΔKe

-1.602 * 10^-17 = ΔKe

**½mv^2 (f) -**

½mv^2 (f) = -

**½mv^2 (i) = 1.602 * 10^-17**½mv^2 (f) = -

**1.602 * 10^-17**But if u rearrange for v then the expression inside the square root is negative ???????

c) I don't even know where to start, an alpha particle is 2 protons and 2 electrons???

Any help would be appreciated !!!