# General Thoughts: Mathematics (1 Viewer)

#### Nukeboy

##### Member
I got 44404, using r = (1.01) / (1.003)
YAY. did the same. Took me a while though.
Hopefully, that's correct.

#### nolimits

##### Member
what was the bearing guys? 322 degrees?

#### Zeref

##### Stare into my eyes.
These estimate for cutoffs, are they out of 120 or 100?

#### hi im trash

##### Member
44404~ for superannuation too, hopefully its correct. and the bearing i think i got 333~? i dont relaly remember x.x

#### trungduong12

##### Active Member
hey guys sorry about my first post: here is the paper uploaded again :
View attachment 31133
THANK YOU !!!
Could someone please do the answers and post it too???

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#### sramisetty

##### New Member
44404 and 333 as well! That's a small relief, hope we're all right.

#### Popcornn

##### New Member
how the fuck do you deduce 15)iv) sqrtA=sqrA1+sqrtA2

#### photastic

##### Well-Known Member
how the fuck do you deduce 15)iv) sqrtA=sqrA1+sqrtA2
Add the two equations, factorise out the x + y and bam magic

#### hi im trash

##### Member
@onlyhereforestimate
i think the a was like.. (1.xx)^59 ??? i think it was 1.01... gah my memory is so bad q.q

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#### PotatoAlpha

##### New Member
what was your A?
If i recall correctly, the full sum was 500(1.003) ( (1.01/1.003)^60 - 1) / ((1.01/1.003) - 1)

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#### harrypotterfan

##### Active Member
how the fuck do you deduce 15)iv) sqrtA=sqrA1+sqrtA2
You get y/(x+y) and x/(x+y)

add them up and its (x+y)/(x+y) =1

That means that root a2/root a = root a1/ root a =1

Hence root a= root a1 + root a2

#### photastic

##### Well-Known Member
Can u upload answer for q15 and 16???

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I'll upload it tonight if no one does it before then

#### lekawaiicupcake

##### New Member
The 10 for the numerator
For the simplest exact value, I'm pretty sure it's correct as long as the numerator and denominator can't cancel out anymore, i.e. factorisation of the numerator isn't required.

#### anthonygonzal

##### New Member
For the bearing question, if you did the bearing from A to C instead of C to A, would that be a straight 0/3? Can't believe I did that...

And also just for curiosity what would a raw mark of ~90 align to?

#### Nukeboy

##### Member
If i recall correctly, the full sum was 500(1.003) ( (1.01/1.003)^60 - 1) / ((1.01/1.003) - 1)
Shouldn't it be 1.003^60 outside the bracket?

#### yma

##### Member
x=60/(24+5pi)
y=(60-10pi)/(24+5pi)
Yeah! I got this, as well

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