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Inhuman

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that Q was a bit screwed up I thought.

The horizontal speed was the gradient of the graph they gave you (dx/dt=v) but I wasn't sure what to do with my own graph- it was a straight line relationship but I wasn't sure whether they wanted units or what
 
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ND

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I fudged that graph, i just drew a line trhough (0, 0) and (.6, 1.85) or whatever it was.
 

Leon585

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um 2. something i think although i could be wrong which i typically am
 

Ragerunner

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Originally posted by ND
I fudged that graph, i just drew a line trhough (0, 0) and (.6, 1.85) or whatever it was.
LOL. Same.

I had no idea.

I couldn't even do the one above that. calculate the horizontal velocity

35oiunh25y3y9859yh32q5hi8w3h2oh35#@%#!$!
 
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i think the answer for the first part........was simply the gradient.....that is, 1.85m/s.....u know, rise over run........not too sure but wat u rekon??......the grpah was fuked and even the question after that
 

Belle

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LOL that question was the biggest guess ever... I just did the same as ND and drew a straight line through (6, 12).

I got 12 m/s for the horizontal speed using delta x = Uxt. It looked like projectile motion so i used that :p it's probably wrong though.
 
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ND

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Originally posted by Ragerunner
LOL. Same.

I had no idea.

I couldn't even do the one above that. calculate the horizontal velocity

35oiunh25y3y9859yh32q5hi8w3h2oh35#@%#!$!
I'm pretty sure we're right though.
 

McDaddy

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Originally posted by ND
I fudged that graph, i just drew a line trhough (0, 0) and (.6, 1.85) or whatever it was.
Yeh I did the same thing, hope that's right!
 

Inhuman

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I did the 'draw a random straight line passing through 0,0 and .6,1.85' too :)

I figured that since they didn't give you graph lines they didn't want it all prettified
 

smeyo

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for the drawn graph linear with gradient as t, yeah thats what i did for the graph to with (0,0) and (0.6,1.85) which gives gradient t
for th horizontal velocity it was d/t which was the grdient 1.85
 

Belle

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Damn, I didn't even think of using the gradient! Must have been a massive brain fart or something, that's so basic! Stupid me.
 
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ND

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Originally posted by Belle
Damn, I didn't even think of using the gradient! Must have been a massive brain fart or something, that's so basic! Stupid me.
If you drew a line through (0, 0) and (.6, 1.85), then you drew a line with gradient t.
 

Takuya

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The bunch of straight lines of different lengths looked stupid but they were right :p

I spent some time thinking about this too... Because it's horizontal velocity versus distance, and horizontal velocity is constant, i.e. flat line.
 

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