help with this qn (1 Viewer)

[bos1234]

find the primitive function of

x^a . x^b

all i know is
(x^a)^b

=(x^a)^b+1 / b+1

what i do after this step?

 

[oobaga]

its not (x^a)^b
because it's a multiplication the powers are added
so it should be (x^(a+b))dx
and then im not so sure wat to do after that

perhaps... x^(a+b)/a+b

good luck
could u send me the answer wen u find out?
Thanks

 

[Raginsheep]

x^a . x^b = x^(a+b)

Since the primitive is the "opposite" of the derivative, d/dx f(x) = x^(a+b)

Since your derivative has degree a+b, primtive has degree a+b+1

Thus if f(x) = x^(a+b+1), the derivative of f(x) is (a+b+1) . x^(a+b)

Therefore to get rid of the (a+b+1) at the front, let f(x) = (x^(a+b+1)) / (a+b+1)