please sketch the inverse relation for this function......
i heard some1 says the trick to draw inverse function is to rotate ur paper somehow, but i dont no exactly......
can any1 tell me if u no the method?
also,how u guys usually start drawing inverse trig function?
u find the domain and range first?
if u r given a graph like above, how do u skecth its inverse cos, tan etc.....
OABC is a square. O represents the complex 0
A represents the complex NO. 3+i, B represents a complex number z and C represents the complex NO. w
D is the point of the intersection of the diagonals.
i) find the complex numbers corresponding to points C and D in the form x+iy
ii) find arg(w/z)
iii) if E is the fourth vertex of the parallelogram OAEB find the complex number corresponding to E….
just wondering the last bit,(iii) ,how many points would u find for E?
isn't it the square itself a parallelogram,so E could be at C?