stupid_girl
Member
- Joined
- Dec 6, 2009
- Messages
- 124
- Gender
- Undisclosed
- HSC
- N/A
For this integral, some trig identities may make your life easier. Of course, Weierstrass substitution will also work.
It seems no one has attempted yet. This one is a little bit interesting.#83 and #88 are still outstanding and this is a new one.
Feel free to share your attempt.
The answer is:This one is slightly tedious.
Where are you pulling these questions from?New integral:
New integral:
I'll leave the intended solution for someone else to write out (p.s I think you need to be a bit careful about the first part, the integrals are indefinite so equality will only hold up to a constant as written.)For , let
Prove that
Given that
Show that
Yep, works super well for these integrals with logs.is that Leibnitz?