log function (1 Viewer)

Joined
Jan 13, 2011
Messages
354
Gender
Male
HSC
N/A
yeh

for x<0 , |x| = -x

therefore f(x) = ln(x^2) / -x


f(x) = - ln (x^2) / x

u= ln(x^2)
du/dx= 2/x
v= x
dv/dx= 1

f ' (x) = - [ ( 2 - ln(x^2) ) ] / ( x^2 )
sub x=-e into that
 
Joined
Jan 13, 2011
Messages
354
Gender
Male
HSC
N/A
similarly , between the limits of -1 and -e , |x| = -x

therefore

we want to integrate - [ln(x^2) / x] dx

then sub u= ln(x^2)

du/dx= 2/x

so dx= x du/ 2

so we want to integrate -u/2 du , and remember to change the limits of the integral
 
Last edited:

Users Who Are Viewing This Thread (Users: 0, Guests: 1)

Top