• Want to take part in this year's BoS Trials event for Maths and/or Business Studies?
    Click here for details and register now!
  • YOU can help the next generation of students in the community!
    Share your trial papers and notes on our Notes & Resources page

Need help in series and sequences (1 Viewer)

joto

New Member
Joined
Apr 21, 2011
Messages
5
Gender
Male
HSC
2013
The rungs of a ladder decrease uniformly in length from 40 cm at the bottom rung to 30cm at the top rung. How many rungs are there if their total length is 5.25m?
 

Aesytic

Member
Joined
Jun 19, 2011
Messages
141
Gender
Male
HSC
2012
your first term is 40cm
.'. a = 40
your last term is 30cm
.'. l = 30
the sum of the lengths of your rungs is 5.25m, or 525cm
therefore 525 = n/2*[a+l]
= n/2*[30+40]
=35n
.'.n=15
.'. 15 rungs
 

Users Who Are Viewing This Thread (Users: 0, Guests: 1)

Top