# Question 11 (1 Viewer)

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#### superSAIyan2

##### Member
i got
a) 3 - 2iroot3 =, 2cis (pi/3) and 2^24
b) A = 4, b=-3 and c=-1
c) (z+2i)^2 - (3i)^2 = (z-i)(z+5i)
d) 2/15
e)x^2 - y^2 =< 4

I used wolfram and it said that for e) you had to shade the region outside of the curve x^2 - y^2 = 4. But i shaded the region between the curve and the asymptotes. Would i lose a mark here? I made a similar mistake in my half yearlies but the teachers still gave me full marks. Would the hsc markers do this too?Í

#### yasminee96

##### Active Member
what would be the "simplest form" for (a) (iii)?

#### yasminee96

##### Active Member
Hmm... I wrote 16777216... Is that not also simplest form considering essentially it's the same thing ? :/

#### superSAIyan2

##### Member
i wrote the actual number in the exam, except i didnt have a calculator with me when i typed my answers. i just remembered 2^24

##### Member
I wrote 16777216 to be safe. I wonder if 2^24 would be accepted.

#### AnimeX

##### Member
I wrote 16777216 to be safe. I wonder if 2^24 would be accepted.
Probably will, 2^24 looks nicer and I guess it's more simple

#### RealiseNothing

##### what is that?It is Cowpea
I wrote 16777216 to be safe. I wonder if 2^24 would be accepted.
Both will be accepted.