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question 27 (1 Viewer)
- Thread starter connie
- Start date
your answer for ii depends on what you thought i was.
Sooooooo....there are two ways you could've done b) i.
What is the probability that neither shows a 6.
You could look at it this way:
there are 6 sides to a dice, so you have 5 out of 6 chance of not rolling a 6.
so it would be 5/6 * 5/6
= 25/36 ( i think thats what you meant to type......
BUT, that doesnt necessarily work cos ONE of the dice may turn to 6
So you have to work out:
P(6,6)= 1/6 * 1/6
= 1/36
So THEREFORE probability NEITHER is a 6 is 35/36.
Then,
ii)
1/36 * $20
1/6 * $2
35/36 * -$2
= -$1.06
so i dunno, this could be the answer or it could not
Comments please.
Sooooooo....there are two ways you could've done b) i.
What is the probability that neither shows a 6.
You could look at it this way:
there are 6 sides to a dice, so you have 5 out of 6 chance of not rolling a 6.
so it would be 5/6 * 5/6
= 25/36 ( i think thats what you meant to type......
BUT, that doesnt necessarily work cos ONE of the dice may turn to 6
So you have to work out:
P(6,6)= 1/6 * 1/6
= 1/36
So THEREFORE probability NEITHER is a 6 is 35/36.
Then,
ii)
1/36 * $20
1/6 * $2
35/36 * -$2
= -$1.06
so i dunno, this could be the answer or it could not
Comments please.
I got
1/36 chance of making $20
5/36 chance of making $2
25/36 chance of losing $2
which means you will lose 56 cents
Dammit: to win $2.00 probabilty of getting a 6 is more then 1/6 because you role 2 dice, which will increase your chance.
1/36 chance of making $20
5/36 chance of making $2
25/36 chance of losing $2
which means you will lose 56 cents
Dammit: to win $2.00 probabilty of getting a 6 is more then 1/6 because you role 2 dice, which will increase your chance.
Last edited:
connie
Member
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but we are talking about different things? so the probability didn't have to add up to 1? there is more then 5 in 36 chance of getting one 6!!!
1,6 2,6 3,6 4,6 5,6 6,1 6,2 ,6,3, 6,4 6,5 which is 10/36? oops so my 11 was one off! damn
but 1/36 + 10/36 + 25/36 = 36/36 or 1?!!!
yours don't add up so i think i've got the answer
1,6 2,6 3,6 4,6 5,6 6,1 6,2 ,6,3, 6,4 6,5 which is 10/36? oops so my 11 was one off! damn
but 1/36 + 10/36 + 25/36 = 36/36 or 1?!!!
yours don't add up so i think i've got the answer
Gregor Samsa
That Guy
I got the same answers, so hopefully it isn't incorrect.
M
mushi
Guest
ok i got -0.27
to win $20 -( 1/6 x 1/6*20 = 1/36
to win 2, it is ( 1/6 x 5/6*2 ) + ( 5/6 X 1/6 ) = 10/36 ( since u can get a 6 on the first try , and a 6 on a second try, therefore 2 ways..if u get what i mean
to lose $2 (5/6 x 5/6*-2 ) = 25/36
then do the right calculations u get -0.27..
hope its right
to win $20 -( 1/6 x 1/6*20 = 1/36
to win 2, it is ( 1/6 x 5/6*2 ) + ( 5/6 X 1/6 ) = 10/36 ( since u can get a 6 on the first try , and a 6 on a second try, therefore 2 ways..if u get what i mean
to lose $2 (5/6 x 5/6*-2 ) = 25/36
then do the right calculations u get -0.27..
hope its right
Last edited by a moderator:
honky tonk
in Miracle World
I might be misreading the question, but didn't it ask for neither die showing a 6? Doesn't that mean that there are 11 chances out of 36 that at least one will show a 6? Have a look:
6, 1
6, 2
6, 3
6, 4
6, 5
6, 6
1, 6
2, 6
3, 6
4, 6
5, 6
Total of 11
36 - 11 = 25
25/36?
honky tonk
in Miracle World
*LoL* I got that too, so we're in the same boat at least.
I've calculated an 83.. a bit lower than I was hoping, but i'm still semi-satisfied.