# Section I - Multiple Choice (1 Viewer)

#### Rafy

##### Retired
Share your multiple choice responses here

lol

Bcbabdccbb

guessed 7 and 10

b
a
d
a
b
d
c
c
b

#### bunnypacman

##### Member
b
a
b (got through half my working out and ran outta time so had to guess)
b
d
c
c
c (another guess)
? (cant remember what i put for 10 cause it was a guess :/ )

#### panda15

##### Alligator Navigator

Completely guessed 10.

b
a
d
a
b
d
c
c
a
b(no idea)

#### Siddy123

##### Active Member
i guessed d for 10
what was the answer to that revs per minute q?

#### Locus

##### Member
i guess d for q10 as well - looked like a nice number

#### BlugyBlug

##### Active Member
1b 2a 3d 4a 5b 6(?) 7c 8c 9b 10d (guess)

Forgot what i put for 6, pretty sure it's D though but i just did it now.

revs per minute = 100pi
v=rw
r=5, (period = 2pi/w) period was given so w =20pi

First time I've seen a pure circular motion q in a HSC paper lols.

#### pHyRe

##### Active Member
D was defs wrong for q 10 i reckon, i saw it and realised it was 2^12, or 4GB = 4096 MB so it was there to trick us im pretty sure. I think i guessed C.... whatevs. fuck that

#### hyphea

##### Member
D was defs wrong for q 10 i reckon, i saw it and realised it was 2^12, or 4GB = 4096 MB so it was there to trick us im pretty sure. I think i guessed C.... whatevs. fuck that
yep same here

#### Trebla

I think the answer to Q10 is (C).

#### study1234

##### Member
Can someone please explain Question 10?

#### psychotropic

##### Member
the answer to 10 is b

#### Trebla

First consider the unrestricted case. We have six people going into four rooms and each person has four choices which gives 46.

Now subtract the cases where the restriction of 4 people per room is broken.

Case 1 - We have 5 people + 1 person. If we fix 5 people to be in the first room, the 1 person can go into the three other rooms. Similarly, if we fix the 5 people across the other rooms etc leading to 4x3 possibilities. However there are six possible people who can be that 1 person so there are 6x4x3 possibilities altogether.

Case 2 - We have 6 people and there are four possibile rooms they can be in.

Altogether we get 46 - 6x4x3 - 4 = 4020

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#### psychotropic

##### Member
First consider the unrestricted case. We have six people going into four rooms and each person has four choices which gives 46.

Now subtract the cases where the restriction of 4 people per room is broken.

Case 1 - We have 5 people + 1 person. If we fix 5 people to be in the first room, the 1 person can go into the three other rooms. Similarly, if we fix the 5 people across the other rooms etc leading to 4x3 possibilities.

Case 2 - We have 6 people and there are four possibile rooms they can be in.

Altogether we get 46 - 4x3 - 4 = 4080
Case I is incorrect as you have to consider which person is excluded. this means that you have to multiple case 1 by 6, yielding 4020