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2 Unit Revising Marathon (3 Viewers)

MrBrightside

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Re: 2 Unit Revising Marathon HSC '10

Solve: |x -5| = 3
 

MrBrightside

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Re: 2 Unit Revising Marathon HSC '10

Easy

|x - 5 | =3

Part one

x-5=3
x=8

Part two

x-5=-3
x=2

Therefore x= 2, 8
correct, you know this question on maths online, is taught the incorrect way. I saw it today and was like woah that's the wrong way, and its up there on maths online. They changed +- on the end number. Like you did.

I prefer this though:

x-5 = 3
OR​
-(x-5) = 3​

x = 8
OR​
-x + 5 = 3
-x = -2
x = 2​

Therefore x = 2 or x = 8

Both ways work, but I've been told that doing it the way I did it solves confusion when people do the other way.
 
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MrBrightside

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Re: 2 Unit Revising Marathon HSC '10

Find the integral of sec^2(5x) dx
 

powlmao

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Re: 2 Unit Revising Marathon HSC '10

correct, you know this question on maths online, is taught the incorrect way. I saw it today and was like woah that's the wrong way, and its up there on maths online. They changed +- on the end number. Like you did.

I prefer this though:

x-5 = 3
OR​
-(x-5) = 3​

x = 8
OR​
-x + 5 = 3
-x = -2
x = 2​

Therefore x = -2 or x = 8

Both ways work, but I've been told that doing it the way I did it solves confusion when people do the other way.
When using absolute values x is always greater than zero otherwise you will get

| x - 5 |

sub -2 in

| -2 - 5 |

= |-7 |
=7
and 7 isn't equal to 3

Looking at your answer again, i believe you just made a typo
 
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MrBrightside

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Re: 2 Unit Revising Marathon HSC '10

When using absolute values x is always greater than zero otherwise you will get

| x - 5 |

sub -2 in

| -2 - 5 |

= |-7 |
=7
and 7 isn't equal to 3

Looking at your answer again, i believe you just made a typo
ahh yeah sorry typo sorry. Fixed.
 

powlmao

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Re: 2 Unit Revising Marathon HSC '10

ahh yeah sorry typo sorry. Fixed.
haha it is fine :p

Maths isn't easy to type on computers.

New one

A function ƒ(x) is defined by ƒ(x) =2x2(3– x).
(i)
Find the coordinates of the turning points of y =ƒ(x) and determine their nature.
(ii)
Find the coordinates of the point of inflexion.
(iii) Hence sketch the graph of y =ƒ(x), showing the turning points, the point of inflexion and the points where the curve meets the x-axis.
(iv) What is the minimum value of ƒ(x) for –1 ≤x ≤4?
 

MrBrightside

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Re: 2 Unit Revising Marathon HSC '10

haha it is fine :p

Maths isn't easy to type on computers.

New one

A function ƒ(x) is defined by ƒ(x) =2x2(3– x).
(i)
Find the coordinates of the turning points of y =ƒ(x) and determine their nature.
(ii)
Find the coordinates of the point of inflexion.
(iii) Hence sketch the graph of y =ƒ(x), showing the turning points, the point of inflexion and the points where the curve meets the x-axis.
(iv) What is the minimum value of ƒ(x) for –1 ≤x ≤4?

Do you multiply that to become 4x? Or do you just treat it as u = 2x , v = 2(3-x)
 
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powlmao

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Re: 2 Unit Revising Marathon HSC '10

Sorry it is meant to be f(x) = 2x^2 (3-x)

I copied it straight from a past paper.
 

SpiralFlex

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Re: 2 Unit Revising Marathon HSC '10



i.

For stationary points,

Hence,







When

When



At

Hence is a minimum turning point.

At

Hence, is a maximum turning point.


ii. For possible points of inflexion,





When

As

As

Hence a change of concavity has occurred, so is a point of inflexion.


iii. Cannot draw as we are online.


iv. When

When

Minimum value is .

This one is quite interesting for 2U students,



Calculate the exact volume formed by the curve bounded by the lines and .
 
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powlmao

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Re: 2 Unit Revising Marathon HSC '10

Wouldn't have a clue how to start that one.
 

powlmao

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Re: 2 Unit Revising Marathon HSC '10

Think deeply.
My school is only up to functions! (We have done barely anything)

Other than that I just know most of Trig, intergration, differeniation and probability
 

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