ITT: Post Mathematics (2U) Questions/Problems (1 Viewer)

[iBibah]

Noticed similar threads for other subs, so why not 2u

 

[LoveHateSchool]

Great idea, sure I will be hitting this up this weekend!

 

[Carrotsticks]

Red leader, standing by.

 

[rsagar]

Shockwave... STANDING BY !

 

[iBibah]

I might as well start with a question for people to attempt.

 

[rsagar]

you have to somehow get 1/2 x base = (r + square root of r^2 - x^2)

hmmm... i'm working on it...

 

[SpiralFlex]

 

[rsagar]

^ Is this a legit real Q. ???

 

[SpiralFlex]

^ Is this a legit real Q. ???

Uh yeah? It's maximum/minimum (2U course)

 

[rsagar]

I might as well start with a question for people to attempt.

1/2B = x (so that's done)
to find the vertical height:
rotate r to make it horizontal the ad r + y which is the formula of the circle
there for h = (r + sq. root r^2 - x^2)
if you get what i mean

 

[Leffife]

Uh yeah? It's maximum/minimum (2U course)

Wow I really love that question, very unique in someway. Is there any chance that I could save her for you? No terms and conditions applied

 

[RealiseNothing]

1/2B = x (so that's done)
to find the vertical height:
rotate r to make it horizontal the ad r + y which is the formula of the circle
there for h = (r + sq. root r^2 - x^2)
if you get what i mean

r is just the radius. So the height of the triangle is just r+y, and use pythagoras to find y, and then the solution falls out straight away.

 

[iBibah]

1/2B = x (so that's done)
to find the vertical height:
rotate r to make it horizontal the ad r + y which is the formula of the circle
there for h = (r + sq. root r^2 - x^2)
if you get what i mean

no need to explain to me, i wrote the question lol

just for people to have a go at

but yes your right so far (and note what realisenothing said)

 

[RealiseNothing]

no need to explain to me, i wrote the question lol

just for people to have a go at

but yes your right so far (and note what realisenothing said)

You made this question? It's very nice imo. I might come up with one of my own soon.

 

[iBibah]

You made this question? It's very nice imo. I might come up with one of my own soon.

Yeh i did, there is a second part that i will post as soon as i solve it.

 

[twinklegal19]

I got x=sqrt(3)/2 r

is that right so far?

probably made a silly mistake somewhere

 

[iBibah]

I got x=sqrt(3)/2 r

is that right so far?

probably made a silly mistake somewhere

nope you're correct for part b

 

[twinklegal19]

nope you're correct for part b

oh good

I thought it would turn out a mugly number haha

 

[GoldyOrNugget]

You want maths? I'll give you maths.

Good luck.

 

[Sy123]

SOLUTION


Very well written question, while people to Spiral's one Ill think of my own