Great explanation
The books I specifically refer to for 3 Unit:Also suggest for any students in Year 11 and 12 taking 2 Unit and 3 Unit, get a copy of Warwick Marlin's formulae book for Year 11 and Year 12 (2 separate books), they are about 60 pages each book. It has every formula you need to remember for the course. (The cost is $10 per book and you can get it pretty much at any Dymocks store). Even when I do the questions , I have to time from time refer to the formula book, its also a good way of refreshing your memory on key concepts.
Here is a link to the books:
https://www.understandingmaths.com/catalog
How come there's no book for extension 2?The books I specifically refer to for 3 Unit:
Facts and Formulas Year 11 Extension 1 (2&3 Unit)
ISBN: 9781875462216
and
Facts and Formulas Year 12 Extension 1 HSC
ISBN: 9781875462230
Can you please answer my question?Someone please help me with this???
So what was the problem you had with the question originally?
Ok let's start with f(x)=(x-2)2 for x < 2. What did you get for the inverse function f-1(x)?Okay I am very confused with this:
1. Find the inverse function f^-1(x) of each function and verify that f^-1(f(x))=f(f^-1(x))=x
a. f(x)=(x-2)^2, x is less than or equal to 2
b. f(x)=x(x+2), x is greater than or equal to 1
c. f(x)=(x-1)^2+2, x is greater than or equal to 1
Okay Gimme a minCan you please answer my question?
Do I answer both your Questions Trebla or what?Can you please answer my question?
BUMPOkay I am very confused with this:
1. Find the inverse function f^-1(x) of each function and verify that f^-1(f(x))=f(f^-1(x))=x
a. f(x)=(x-2)^2, x is less than or equal to 2
b. f(x)=x(x+2), x is greater than or equal to 1
c. f(x)=(x-1)^2+2, x is greater than or equal to 1
The answers aren't on the sheet David so idk what the answers are
The answers aren't on the sheet David so idk what the answers are
BumpOk let's start with f(x)=(x-2)2 for x < 2. What did you get for the inverse function f-1(x)?
Yes. That question you managed to answer yourself, what was the problem you had with it originally that prompted you to ask it?Do I answer both your Questions Trebla or what?
if you are referring the question with the cubic I think that problem was that I expanded it out by accident when I wasn't supposed toYes. That question you managed to answer yourself, what was the problem you had with it originally that prompted you to ask it?
I'll try it hereBump
You needed to take the negative square root, since y needed to be ≤ 2.I'll try it here
y=(x-2)^2, x <_ 2
Switch x and y around
x=(y-2)^2, y <_ 2
Squareroot of x=y-2, x <_2
squareroot of x+2=y
y=squareroot of (x) +2
Given our condition is x <_2 we can only have one case
Okay wtf am I doing wrong
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