The Code Marathon. (2 Viewers)

[Paradoxica]

Write a method/program which displays Pascal's triangle up to n rows, n a given positive integer.

It was never stated we had to write out the integers themselves... Could also leave it in binomial coefficient notation...

 

[turntaker]

Java sucks. C for life

 

[parad0xica]

Question: write a program to count the number of words in a text file.

 

[Rhinoz8142]

public static void main

{
count words;
++count
}

 

[Rhinoz8142]

jks

 

[FlyingKanga]

Question: write a program to count the number of words in a text file.

Java:

import java.util.*;
import java.io.*;
public class wordCount {
	public static void main(String[] args) {
		File newFile = new File(args[0]);
		int count = 0;
		try {
			Scanner scan = new Scanner(newFile);
			while (scan.hasNext()) {
				String word = scan.nextLine();
				String[] words = word.split("\\s+");
				count += words.length;
			}
		} catch(Exception err) {
			System.out.println("Not found");
		}

		System.out.println("Total words: " + count);	

		}
	}

 

[Drsoccerball]

Question: write a program to count the number of words in a text file.

C code :

#include <stdio.h>
#define MAX_CHARACTERS 1000
#define MAX_LINE 100

int main(int argc, char *argv[]){
	FILE *stream = fopen(argv[1], "r");

	if(stream == NULL){
		printf("The file %s doesn't exist.\n", argv[1]);
		return 1;
	}
	char file[MAX_LINE][MAX_CHARACTERS];
	int j = 0;
	while(fgets(file[j], MAX_CHARACTERS, stream) != NULL){
		j++;
	}
	int i = 0;
	j = 0;
	int character = 0;

	while(file[j][i] != '\0'){
		while(file[j][i] != '\0'){
			if((file[j][i] >= 'a' && file[j][i] <= 'z') || (file[j][i] >= 'A' && file[j][i] <= 'Z')){
				character++;
			}
			i++;
		}
		i = 0;
		j++;
	}
	printf("The text file %s has %d characters.\n", argv[1],character);
	fclose(stream);
	return 0;
}

 

[Drsoccerball]

Write a method/program which displays Pascal's triangle up to n rows, n a given positive integer.

Do this but with letters.
./triangle 3
A
BCB
DEFED
(Click reply to quote to see how the triangle should look)
When the letter reaches Z loop around.

 

[parad0xica]

C code :

#include <stdio.h>
#define MAX_CHARACTERS 1000
#define MAX_LINE 100

int main(int argc, char *argv[]){
	FILE *stream = fopen(argv[1], "r");

	if(stream == NULL){
		printf("The file %s doesn't exist.\n", argv[1]);
		return 1;
	}
	char file[MAX_LINE][MAX_CHARACTERS];
	int j = 0;
	while(fgets(file[j], MAX_CHARACTERS, stream) != NULL){
		j++;
	}
	int i = 0;
	j = 0;
	int character = 0;

	while(file[j][i] != '\0'){
		while(file[j][i] != '\0'){
			if((file[j][i] >= 'a' && file[j][i] <= 'z') || (file[j][i] >= 'A' && file[j][i] <= 'Z')){
				character++;
			}
			i++;
		}
		i = 0;
		j++;
	}
	printf("The text file %s has %d characters.\n", argv[1],character);
	fclose(stream);
	return 0;
}

My bad. I should have defined what a word means. A word is a string containing no spaces.

"Mathematics is fun. Have a nice day, G." contains 8 words

 

[turntaker]

Create a compiler that compiles a programming language you made up.

 

[Drsoccerball]

My bad. I should have defined what a word means. A word is a string containing no spaces.

"Mathematics is fun. Have a nice day, G." contains 8 words

Im pretty sure my program does this? I accidentally wrote 'characters' instead of 'words' though.

EDIT: brb

 

[Drsoccerball]

My bad. I should have defined what a word means. A word is a string containing no spaces.

"Mathematics is fun. Have a nice day, G." contains 8 words

My code assumes that only valid inputs are given .

#include <stdio.h>
#include <ctype.h>
#define MAX_CHARACTERS 1000
#define MAX_LINE 100

int main(int argc, char *argv[]){
	FILE *stream = fopen(argv[1], "r");

	if(stream == NULL){
		printf("The file %s doesn't exist.\n", argv[1]);
		return 1;
	}
	char file[MAX_LINE][MAX_CHARACTERS];
	int j = 0;
	while(fgets(file[j], MAX_CHARACTERS, stream) != NULL){
		j++;
	}
	int i = 0;
	j = 0;
	int character = 0;

	while(file[j][i] != '\0'){
		while(file[j][i] != '\0'){
			if(((file[j][i] >= 'a' && file[j][i] <= 'z') || (file[j][i] >= 'A' && file[j][i] <= 'Z'))){
				if(isspace(file[j][i + 1]) != 0){
					character++;
				}
			}
			else if(((file[j][i - 1] >= 'a' && file[j][i - 1] <= 'z') || (file[j][i - 1] >= 'A' && file[j][i - 1] <= 'Z'))){
				if(isspace(file[j][i + 1]) != 0){
					character++;
				}
			}
			i++;
		}
		i = 0;
		j++;
	}
	printf("The text file %s has %d words.\n", argv[1],character);
	fclose(stream);
	return 0;
}

 

[parad0xica]

That's better but it still fails for a text-file containing:

Mathematics is fun. Have a nice day, G.

Your program produces 7.

 

[Drsoccerball]

That's better but it still fails for a text-file containing:

Mathematics is fun. Have a nice day, G.

Your program produces 7.

I don't want to abuse the if statements so ill leave my program broken

 

[FlyingKanga]

That's better but it still fails for a text-file containing:

Mathematics is fun. Have a nice day, G.

Your program produces 7.

Mine works right? It just splits each word whenever there's a space in between. But then it'll have day, as a word .-.

 

[parad0xica]

Mine works right? It just splits each word whenever there's a space in between. But then it'll have day, as a word .-.

seems right

 

[turntaker]

instructions not clear enough, accidentally created my own OS

Sent via i1337OS

me too thanks

 

[KingOfActing]

Create a compiler that compiles a programming language you made up.

low key want to do this

I'll make brainfuck 2.0

 

[Flop21]

bump

 

[KingOfActing]

I'm not quite sure what you mean

To do Key-Value mappings I'd just use a HashMap, why recreate the wheel? Also why the "no method" restriction? Do you mean no static methods or no methods at all? None at all means you can't even print anything... Unless you meant no creation of ADDITIONAL methods, in which case the following (awful) code would fit all the requirements:

public class Entry
{
    public final K key;
    public final V value; 

    public Entry(K key, V value) {
        this.key = key;
        this.value = value;
    }
}

Then your "app" would have an array of these, it would cycle through them and compare keys to the input key, and once a match is found the value is printed.

This implementation is not OO though. The key idea of OOP is that objects aren't just 'things' that hold data - objects are defined by behaviour and well, this object has none. not to mention it's completely inefficient - like I said, don't reinvent the wheel!

_{Why am I not studying for my trial tomorrow?}