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AlarmBell
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Recent content by AlarmBell
A
Derivatives
For part (iii): $\noindent \int_{4}^{6} f'(x)dx = f(6) - f(4) = -6, (A_3 = 2*3) \\ \\Since \int_{2}^{4} f'(x)dx = -\int_{0}^{2} f'(x)dx \\ \\ \int_{0}^{2} f'(x)dx = f(2) - f(0) = 4 \\ \\ Given f(0) = 0 \\ \\ \therefore f(2) = 4 \\ \\ \int_{2}^{4} f'(x)dx = f(4) - f(2) = -4 \\ \\ \therefore f(4)...
AlarmBell
Post #2
Jun 10, 2016
Forum:
Mathematics Advanced
A
Answer AlarmBell's Questions Thread
Thank you InteGrand! <3 Much appreciated.
AlarmBell
Post #8
Mar 27, 2016
Forum:
Maths
A
Answer AlarmBell's Questions Thread
Hey can anyone help me with these 2?
AlarmBell
Post #6
Mar 26, 2016
Forum:
Maths
A
Answer AlarmBell's Questions Thread
Thank you very much InteGrand! :)
AlarmBell
Post #5
Mar 26, 2016
Forum:
Maths
A
Answer AlarmBell's Questions Thread
Hey, thanks for your reply! I don't fully get it. Sorry but could you explain further with full working out please?
AlarmBell
Post #3
Mar 26, 2016
Forum:
Maths
A
Answer AlarmBell's Questions Thread
Hey there can anyone help me with this question? [emoji4] Cheers, AlarmBell.
AlarmBell
Thread
Mar 26, 2016
Replies: 7
Forum:
Maths
A
"Complex Roots always come in pairs"
$\noindent Complex roots come in conjugate pairs only when the coefficients of the polynomial are real. \\ \\Since the coefficients of (2-i)z^2-(1+i)z+1=0$ $ is complex, the other root is not a conjugate of the one you found.$
AlarmBell
Post #2
Feb 9, 2016
Forum:
Mathematics Extension 2
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