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Collected
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Recent content by Collected
C
help with ANOTHER ruse 4U Q
The ruse solutions say that because they are using the results from part ii (with the t,k - t, k+1) which admittedly is worded pretty badly.
Collected
Post #19
Oct 1, 2014
Forum:
Mathematics Extension 2
C
help with ANOTHER ruse 4U Q
just doing the inductive step (prove true for n=k+1) LHS=(k+1c0)/x - (k+1c1)/x+1 + .... (-1)^(k+1) (k+1)c(k+1)/(x+k+1) = kc0/x - (kc1+kc0)/x+1 + (kc2+kc1)/x+2 .... (-1)^(k+1) (kck)/(x+k+1) as (kck=k+1ck+1) = k!/x(x+1)(x+2)..... - (kc0/x+1 - kc1/x+2 ......) (by assumption) now from ii we...
Collected
Post #15
Oct 1, 2014
Forum:
Mathematics Extension 2
C
FREE notes on 'Romulus', 'Dickinson', 'Crucible', 'AYLI', 'Immigrant Chronicle'!!
Hi, I would like the Emily Dickinson notes please.
Collected
Post #3
Apr 20, 2014
Forum:
Focus: Belonging
C
FREE notes! 'Belonging: HSC Marker's Tips'!
Count me in please!
Collected
Post #17
Dec 31, 2013
Forum:
Focus: Belonging
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