Recent content by dishab

MEGAUPLOAD - The leading online storage and file delivery service2009 Soln MEGAUPLOAD - The leading online storage and file delivery service 2000 Soln

Awww i see. Thnx random-1006

I dont get ii from part a) :(

Hey can someone please help me with this question no. 17 about projectile motion.

I am also doing the same question no. 14. Cant work out part C. Can someone plz work it out... i am kinda lost... :confused:

A ball is dropped from a lookout 180 meters high. At same time, a stone is fired vertically upwards from the valley floor with speed V m/s. Take g = 10m/s^2. a) Find for what values of V a collision in the air will occur. Find, in terms of V, the time and the height when collision occurs, and...

Thnx kcqn93 :jump:

how did u get x = 5 cos(pi - pi/12 t):confused:

The temperature at each instant of a day can be modelled by a SHM function oscillating between 9 degrees at 4:00 AM and 19 degrees at 4:00PM. Find, correct to the nearest minute, the times between 4:00 AM and 4:00 PM when the temperature is 14 degrees. The correct answer is 10AM. I am...

but how do i get in the format they need :confused:

So the question is as follow: If y=In(tan2x), show that dy/dx = 2sec2x cosec2x My attempt: =1/tan2x * 2sec^2 2x I cant get it into the format they want. Any help would be appreciated.

K from carrying on ur answer. =-cos^2x - sin^2x + sinx all over cos^2x = -1 + sinx all over cos^2x. Thats a gud enough answer. :haha:

Thank you untouchablecuz and Iruka. i had the right answer :rofl:

K i am lost.

cos^3 x dx = cos^2x . cosx =(1-sin^2x).cosx = let u = sinx then du = cosx.dx therefore; (1-u^2) du =u-u^3/3 = sin- sin^3/3. wat am i doin wrong?