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Drongoski's latest activity
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DI think you can still use remainder theorem? Factorise the divisor into x(x+1) Using remainder theorem in the original polynomial, we...
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DP(x)/(x^2+x) by polynomial division, and then u will get the remainder.
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Dyeah what yanujw said. The answer should be -2
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DDrongoski replied to the thread What tutor to pick.Yes, I still take students, but only a few.
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DDrongoski replied to the thread Maths Help.3. \frac {dy}{dx} = e^{2y}\\ \\ \therefore \frac {dy}{e^{2y}} = dx \\ \\ \therefore \int dx = \int e^{-2y} dy \\ \\ \therefore x =...
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DDrongoski replied to the thread Maths Help.2. \frac {dy}{dx} = 1 - \frac {y}{3} = \frac {3 - y}{3}\\ \\ \therefore \frac {dy}{3-y} = \frac {dx}{3}\\ \\ \therefore \int \cdots dy...
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DWould the following working help? Part (i): If the two curves have a common tangent, then their derivatives must be equal at that...
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DDrongoski replied to the thread Binomial Distribution Assignment Help.Question too bloody long!
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DDrongoski replied to the thread How do I do this complete mindblank.You can use the "Terry Lee" method to find the square root of -60-32i. Here's how: \sqrt{-32i - 60} = 2\sqrt{-8i -15}\\ \\ \sqrt{-8i -...
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DDrongoski replied to the thread confused with this q.A^4 + 4B^4 = A^4 + 4B^4 + 4A^2B^2 - 4A^2B^2 \\ \\ = (A^2 + 2B^2)^2 - (2ab)^2 = (A^2 + 2B^2 +2AB)\times(A^2 + 2B^2 - 2AB)
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DDrongoski reacted to dan964's post in the thread Is reverse chain rule just integral of product of function and it's derivative? with
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Reverse chain rule would be basically a quick hand way of doing integration by substitution, by inspection. Generally its most useful... -
DDrongoski replied to the thread how to improve in maths.I don't think you can get an easy answer here. If you can afford it, get a good tutor to check you out or a friend who is good in maths...
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DI would recommend using the substitution u=\tan^{-1}(x^3) I=\int{\frac{6x^2}{1+x^6}\times\tan^{-1}(x^3)dx \\let\...
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DDrongoski replied to the thread Is reverse chain rule just integral of product of function and it's derivative?.Maybe I'll show you how to do RCR later.
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DGenerally speaking, if you have a division of polynomials and the polynomial in the denominator can be fully factorised into linear...
