Recent content by drowning_pocoyo

get out of the group and study by urself

LOL detective conan ;D

thatss nice (Y) i dunno for proofs i thought it common to do LHS = RHS

For n = 1 LHS = d/dx (1/1-x) LHS = -1.(1-x)^2.-1 LHS = 1/(1-x)^2 RHS = 1!/(1-x)^2 RHS = 1/(1-x)^2 Hence the statement is true for n = 1 Assuming the statement is true for n = k d^k/dx^k (1/1-x) = k!/[(1-x)^k] For n = k + 1 d^k+1/dx^k+1 (1/1-x) = (k+1)!/[(1-x)^k+1] LHS = d/dx...

come running - darren styles ft francis hill

peace to you to? :)

that was so bad im still laughing at u. dumbass.

wow learn to talk english much? anyway good luck

cant accurately tell until u get assessment ranks and school rank for hsc course

that was such a witty comeback it might possibly (but probably not) made u funny.

you who should clam down theres no need to swear. remembering from last year our school hadnt said anything to us about subject selections.

+1

be safe and keep 12

err id rather not say on the net :L

hahahaha you were so tank! until i got shivas!!! xDD nah it was a good game :) lets ba sometime