For
Q1, the book has it as -3loge |2x-5|+c, where the 2x is positve and the 5 is negative. why is that?
Q2. i don't get the point of this step
y' = 6u^-2.du.(dx/du)
dx/du = -1/2
Q3. same problem as question 1, the book has it as y = -1/3 log|-4+3x| +C
Q4. the back of the said the answer...