Still a bit unsure about the calculations of H+ and OH-, although I think I see where all the values come from.
Thanks very much though, that clears it up a bit.
Calculate the pH of the solution resulting from mixing:
5.0mL of 0.100M H2SO4 and 25.0mL of 0.100M NaOH.
I don't know the answer but I'm pretty sure I've gone wrong somewhere, this is what I did though:
H2SO4 + NaOH --> 2H2O + Na2SO4
n(H2SO4) = C x V = 0.1 x 0.05 = 0.005 Moles
n(NaOH)...