Recent content by Mr.GreyCells

Thanks a lot :)

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This particular question I now understand after you explained it. However, I find the number of moles of substance before dissociation and the moles after dissociation thing confusing. When you make a solution of a substance for eg an acid, wouldn't the water be in dissociated form too thereby...

I had a question: Wouldn't it require more of naoh to neutralise h2so4 than it took to neutralise ch3cooh? like way more than double? Don't know if my question makes sense lol.

Oh I thought neutralization was all about strength of acids and bases.

Wait why did you take the number of moles of H+ ions released by CH3COOH, the same as the number of moles of ch3cooh? Isn't it a weak acid therefore dissociates partially to give CH3COO- and H+ and CH3COOH still remains in the solution?

Thanks for your reply but I can't view the attachment. Do you know where I could get the solutions of Abbotsleigh trial 2021 paper from which this question was taken?

A 25.00 mL sample of 0.100 mol L-1 acetic acid solution needed 22.20 mL of a NaOH solution for complete neutralization. What volume of the same NaOH solution is needed to neutralize 25.00 mL of 0.100 mol L-1 sulfuric acid solution? A. 11.10 mL B. 22.20 mL C. 33.30 mL D. 44.40 mL Thanks

Hi, I just found out that there is a prerequisite of Maths Extension 1 for comp. sci. engineering in UNSW and well, I did Ext 1 in yr 11 and dropped it in yr 12 because it was 1 unit and now I am really really regretting dropping it. Is there any way I could get in without that like a course or...