Recent content by Sakeeee

cool dude explain that to these kids then

if they say find then just take your chord of contact and sub in x0,y0 WHICH THEY ALWAYS GIVE YOU. yeah it's very confusing cause it seems too fucking easy. THE ONLY HARD THING IN CHORD OF CONTACTS IS PROVING IT! OTHERWISE IT'S A JOKE

Do it anyways i mean the fact that you're righting a fake answer means u don't know the real answer. So why not try your luck with ur teacher.

so z1-z2 is a straight line right. now arg (z1-z2) is the angle it makes with the x axis say this angle is 130 degrees. now arg(z1-z4) is the angle made by the line z4z1 and the angle made by this is say 100 degrees against the x-axis. DRAW THESE TWO LINES MAKING SURE ONE IS 130 DEGREES AND...

sub @ as a root a@^3+c@x+d=0 eqn(1) now lets find what @ equals to y'=3ax^2+c x^2=-c/3a that means @^2=-c/3a since @ is the root sub it into eqn 1 a(-c/3a)^(3/2) + c(-c/3a)^(1/2)+d=0 [(-c/3)^3/2]/a^(1/2) + [(-c)^(3/2)]/3a)+d=0 Yeah it's getting hard to simply with this inefficient...

infinity/infinity = anything EXPLAINED! definition of infinity = a large number (WRONG!!! or at least not fully explained) Infinity, in simpleton terms, means a number that u cbf counting too, after all we're humans. Even computers can't count all the numbers out. Therefore, for one person...

concyclic means opposite angles add to 180!!! Thus arg(z1-z2) - arg(z3-z2) + arg(z3-z4) - arg(z1-z4) = 180 .'. arg [(z1-z2)(z3-z4)]/[(z1-z4)(z3-z2)]=180 (using the rules of arg which are so fking similar to log) (z1-z2)(z3-z4)]/[(z1-z4)(z3-z2)= a real number (when given an angle = 180 you...