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Hahaa i remember attempting to use cylindrical shells in one of my 2U test for the lolz last year cos i had heaps of spare time. Yeah i get how you would feel in a 2U class, just try and do some of your own work instead of listening i dunno

lol is this a guy crushing on a guy (not judging or anything) but yeah that kind of stuff happens just keep it a secret, you'll probably get over that feeling soon enough.

wtf is this HAHAHA

Crap i don't remember how to do a formal proof

party with dem CAGs?

ACCT1501 Quiz 1: 7/20 Quiz 2: 4/20 ECON1101 Test 1: 69/15 Yeah :) (jks i don't even do those courses)

at first glance this does not look like SHM lol

My bad :P and I actually don't get your line

How's your discriminate? cause I'm looking for a real root. You are the absolute value of my life, you turn my all negatives into positives ;)

I hate work, so i just sleep early instead and hope for the best the next day with a fresh mind :)

I reckon there would be more people spewing over algebra than calculus :)

Re: MX2 Integration Marathon Hey guys in dat UNSW ASOC integration bee, there was this weird question (carrot would approve) \int \sqrt{x+\sqrt{x+\sqrt{x+...}}} dx

For n = 1 LHS = 1 and RHS = 1 so n= 1 is true Now Assume true for n = k k!\geq 2^{k-1} Prove true for n = k+1, that is (k+1)!\geq 2^{k} LHS = (k+1)! \\ = (k+1)(k)! \\ \geq (k+1)2^{k-1} \ \ \ \ \ \ \ (From assumption)\\ \geq 2.2^{k-1} \ \ \ \ \ \ \ \ \ (k+1\geq 2)\\ = 2^k Therefore...

You start by using the Quadratic formula, so you get z = \frac{-3i\pm \sqrt{(3i)^2-4(2)}}{2} = \frac{-3i\pm \sqrt{17}i}{2}

bump

dame you ask the wolfgang?

Apparently there's a pho place near the round house, but it's closed down, is this true?

Re: HSC 2014 4U Marathon i) No since the output only consist of positive numbers, which is only part of the output domain of the function ii) I think yes haha since you can get a complex number after squaring a complex number iii) No since you'll only result in real values as the output...

it's not very effective.

I do not know the marking criteria as i'm a first year noob. But I would say: For method 2, you should add that all of the elements in the codomain has at least one corresponding value in the domain.