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Did anyone notice that 1a) was the same as 2005's?

For part iii), I saw it as: Total points awarded to all teams = 4 therefore, Home must score >2. Possibilities: 1 Win, 3 Draws = 0.2 * (0.6)^3 2 Wins, 1 Draw = (0.2)^2 * (0.6)^2 3 Wins [Includes 4 wins] = (0.2)^3 Total Possibilities = 0.0656 Not sure if this is right though...

(quoted for emphasis) It's almost like he's making his argument without waffling!