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Would you like to know how the 2005 HSC exams were marked? HSC and SC 2005: Feedback and Advice Saturday 25th February, 2006 Macquarie University – Mason Theatre Free for MANSW members $20 for non-members Program <TABLE cellSpacing=0 cellPadding=5 border=0><TBODY><TR><TD>8:45am...

Yes. That's right. If it's different, a mistake has been made. Students should check their solutions as well as just doing them.

You forgot the remainder. It should be A(x).Q(x)+R, for some number R. If it is a more general divisor, A(x).Q(x)+R(x) where deg(R(x)) < deg(A(x)). The inspection method works for these as well. Just use the last term in Q(x) to get R(x). Also, in your example, I would suggest...

I noticed last night Timbk2 changed the name of the BOS wiki to Biki. That's a funny one! lol.

I can be used for quadratic divisors as well: http://www.purplemath.com/modules/synthetic-division-sgnd.pdf

Ask them at your own risk. Most maths teachers don't know much about maths. Ha! Ha! And I bet most of them would not be capable of proving the formula for the square roots of a complex number. Neverthless, here's the MUCH LONGER SOLUTION...

It's called synthetic division. http://www.purplemath.com/modules/synthdiv.htm http://www.purplemath.com/modules/synthdiv2.htm

No. x<SUP>4</SUP>-16x<SUP>2</SUP>-15<SUP>2</SUP>=0. This part is right!

You can just use the formula and do it in 1 line without mucking about with equations.

You missed the square (which I made red): x⁴-16x²-15²=0.

It's not hard to derive. Square both sides: Or alternatively just follow what pLuvia and Riviet said, but in the general case (a bit longer, but it still works).

My solution to the Coroneos question used 2 formulae simultaneously. Square roots of a complex number, and quadratic formula. You don't have to use the quadratic formula to solve a quadratic, but it's easier in your example if you do. Likewise, you don't have to use the formula for the...

It is in the syllabus. sgn(b) is the sign of b. So if b > 0, sgn(b)=+1, if b < 0, sgn(b)=-1. If b=0, sgn(b)=0, but then there's no need for the formula. Using this formula is a much faster method and so as far as risk is concerned, there's much less chance of making a mistake if you...

It's easier if you use the formula:

In my solution, w=16-30i.

You're right. I was being too generous. It's probably more like 80% who are below average. Riviet was talking about average teachers. If one were to talk about median teachers, I'd say the same about them, i.e., they also know nothing. Also, who_loves_maths's argument is based on the sad...

The average maths teacher knows NOTHING! Ha! Ha! And that's why they shouldn't be teaching! Nevertheless, I am pleased that there are actually some well educated (hence above average) teachers out there, as evidenced in some of the quotes I used in my first post above - who are teaching the...

Because it's not always the most efficient method. Does that include the 5 HSC examples I used? Are HSC questions trivial? Most HSC students wouldn't think so. And the other examples I used were similar to those anyway. On this, I agree. It's better to use testing either side of the...

If you consult your teacher, don't forget to educate them by showing them this thread. If your teacher lets you use the second derivative method, then they should let you use the third derivative method as well. But if they don't let you use the third derivative method then they shouldn't let...