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lol proz..... i m gonna fail physics

well... first complete the square of x(4-x) so it becomes 4-(x-2)2 then substitute x-2=2sin a, x = 2sin(a) +2, dx = 2cos(a) da bounds: x: 0~2, a: -pi/2~0 anyway then sub it back in, the function to be integrated should be ∫ √[4-4(sin a)squared] da ∫ 2 (cos a)squared da hope u get...