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Hmmmm I see. Thanks for the reply. Guess I'll stick with advanced chem then :)

I know that in first year chem, the only difference between adv. and reg. was the content taught in lectures. Is that the same with second year chem?

ahh i see... thanks for clearing it up :D

Really? haha sorry :) hmmm... how does |z- i| and |z - 1| both look like? are they still circles?

{z e C | |z − i| < |z − 1| }?? Thankyou :D

Cool so I'm right? Thanks :D

In an experiment, a student mixed 15.0mL of 0.030mol L-1 HCl with 20.0mL of 0.010mol L-1 Ba(OH)2. Calculate the pH of the resulting solution. The answer is 6.76 but I got 2.845. As you can see I'm way off. Please help :D

Re: HSC 2012 Chemistry Marathon Firstly, to calculate the concentration of Na2CO3 we will need to use the formula c=n/v. Therefore from the given information v= 0.25L, and n will need to be calculated using n=m/M. n(Na2CO3)= 1.432/2(22.99)+12.01+3(16) = 0.0135.... c(Na2CO3)= 0.0135...../0.25...

Your welcome, also yes they can/do pay the first instalment in the same year they borrowed the money hence why the $8000 is multiplied by 1.07. Which means that they are paying back the 8000 they borrowed plus the interest which is calculated before the first instalment. So the first instalment...

A1= $8000x1.07 - M (where M is the yearly repayment) A2= ($8000x1.07 - M)x1.07 - M = $8000x1.072- M(1.07+1) Therefore: An= $8000(1.07)n - M(1.07n-1+......+1) A10=0 $8000(1.07)10 - M(1.079+1.078+.....+1)= 0 M= $8000(1.07)10/1.079+1.078+.....+1 M= $8000(1.07)10/ [1(1.0710 -...

ah I see, thanks for clearing that up, kinda nervous about starting uni.

thanks for the heads up, hopefully they do implement the new elearning app because I just got an ipad for uni :D I just logged in and the only subjects that I'm enrolled in is maths. I thought that lectures aren't recorded for maths?

thanks and another question where are the lectures uploaded?

I'm sorry if this has been asked before but I'm wondering if any of these lectures are recorded: MATH1001 MATH1002 CHEM1901 BIOL10031 BIOL1911 Thankyou! :D

yep think so :)

+1 Just did the bare minimum. Still went fine :) ATAR= 95+

Using arrhenius' definition of an acid, what would NaHCO3 be classified as? Would it be an acid because it releases H+ ions in solution? NaHCO3 (s) → Na+(aq) + H+ (aq) + CO32- (aq)

you mean the 20th? I got the letter as well, wasn't expecting it though :D

She did well considering she had a terrible teacher for chem. I don't think that anybody noticed the typo, even the teacher.

Thanks plus repped :) No wonder I couldn't do it and lol it was in my friend's prelim paper too...