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\text{So you have} \hspace{2mm}\dfrac{1}{\cos x} - \dfrac{\sin x}{\cos x} = \dfrac{3}{5} \dfrac{1- \sin x}{\cos x} = \dfrac{3}{5} \text{Square both sides and get everything in terms of sin x using the identity} \sin ^2 x + \cos ^2 x = 1 \text{It's straight-forward from there. }

What @B1andB2 said ^ I've not seen any tutoring center which is around $15-20, however you can get private tutoring starting from $20 and for English a private tutor is much much better than a tutoring center because English requires a different kind of attention as opposed to the other...

Stop derailing this thread everyone. The user needs genuine help, this is not the place for off topic posting.

\text{R.T.P}\hspace{2mm}{n\choose r} = {n-1\choose r-1} + {n-1\choose r} \text{Start with RHS}\hspace{2mm} = {n-1\choose r-1} + {n-1\choose r} = \dfrac{(n-1)!}{(r-1)!(n-r)!} + \dfrac{(n-1)!}{(n-r-1)r!}\hspace{2mm}\bigg(\text{By using the identity}\hspace{2mm}{a\choose b} =...

So this is why I never got a band 6 in English. Compare this explanation to mine imao

Now I'm not the goto English guy but, I guess they can open your eyes to different parts of the world, their practices, culture etc... These things can be used to further our own understanding in many different areas such as science. Traditional medicine vs Modern medicine is just one of the few...

The equation initially is f(x) = ax^3 + bx^2 +cx + d. Which rearranged is f(x) = ax^3 + cx + (bx^2 + d). If you sub in bx^2 + d = 0 into that equation what remains is ax^3 + cx.

Real Physics basically is Maths except with a different type of intuition. I don't think we should even call HSC Physics a science imao.

Because it says P(x) is an odd polynomial. With an odd function P(x) = -P(x). It also has degree 3. You can only have a degree 3 polynomial of the form ax^3 + bx that is an odd function because P(-x) = a(-x)^3 + b(-x) = -(ax^3 + bx) = -P(x)\hspace{2mm}\text{(Hence satisfying the...

Mostly true but it can still happen. My school ranked 300+ had an amazing Science faculty. We had teachers with Phds from Usyd, Unsw and lots of other great credentials!

Yeah tbh the plot line of Korra at times didn’t feel as well thought out as Aang’s

Personally I never ever used a textbook unless I was forced to by the teacher for homework and what not. Textbook problems are usually much easier than exam problems so imo a textbook should only be used if your trying to learn something.

Adding onto TheShy, a = dv/dt so naturally you need to integrate both sides to get v in terms of t because v and t are what you get when you integrate dv and dt respectively.

There’s no limit but usually people just wanna see you’ve given it a go yourself and tried, maybe your thoughts on how to do it or your own working out so we can see what your doing wrong.

This looks like half or more of the assignment. While we are here to help answer questions and give hints we can’t just do that much of the assignment for you. That would be cheating. After all it is your job to study the content learn it and then if you need help on something we can help you...

Looking at the posts above, I have absolutely no idea what in the world you guys are talking about and at this point I’m too afraid to ask lol

The hell is my calculator doing then...😶

I have no idea what your doing on this line. You don't divide it by 4 because there's 4 tests, but rather by the total percentage. To get the final mark in terms of a percentage you would have to do \dfrac{22.5625}{50} \times 100 = 45.1% because in total the weighting is out of 50. You need...

I know I did cos(pi/5). Seriously just type it in the calculator, it does not equal 1 + sqrt(5)/4

Just plugging iii into my calculator it does not seem to be true. As for part c sub x = u + 1/u and expanding all that gives you u^4 + u^3 + u^2 + u + 1 = 0 which is the same equation as the one in part b, so it obviously has the same roots. You just need to argue as to why there's only the...