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No the vertical component never stops, its acceleration is 9.8ms-2 throughout the flight (assuming that of course the vertical displacement is relatively small). It goes through zero, and yes at top of flight Vy=0, but it doesn't stop! I'll repeat it again, if you're saying that projectile...

Also, I think you should consider the phrase "pot calling the kettle black". You're being so god damn serious. I was just trying to make a point that, unless if you can tell me how long the ball or projectile 'stops' in the air for, then it doesn't stop in the air.

Yes, it goes THROUGH zero; But it never actually stops in the air

Well, if you think about it, it's the same as the projectile being dropped from a height, instead of it starting from the ground and thus Uy=0, but yeah your method probably is better. Theoretically it doesn't stop. Practically, I don't know as it does depend on air resistance and all these...

The projectile never stops in the air. It goes through zero, but never actually stops.

[/SIZE]vy=uy+ayt Where vy=? uy=0 ay=9.8 t=0.57/2 Then use vy2=uy2+2ayΔy, and find Δy I assume they mean initial velocity? [/SIZE]v=sqrt(uy2+vy2) 30 degrees below horizontal.

They may as well attach 'Suggested Answers' at the back of the blood exam!

Everybody has their preferences to what they do; I'm just not a fan of graphs, unless they are required (ie. asked in the question). So, if there's another way it'd be good :P

I did this in Year 11 as one of my last pracs in 'The Cosmic Engine' module, I thought prelim wasn't examinable in the HSC?

I personally think that Jacaranda and other textbooks are sufficient; what's so good about Excel?

Hmm okay, how would I express this algebraically though? Like what I'd write in an exam? I'm not really a fan of doing graphs to show things as I could make mistakes etc..

Series and Sequence is a HSC topic, not prelim. I did it a few weeks ago and got 2nd in the year with 85%. I was only 1 mark off the top and made a VERY STUPID error which lost me a mark! It was a difficult test as you can tell; too bad that I'm doing 4U and it wont count for anything, unless of...

Could someone please help me with these questions? They are from Fitzpatrick EX 36(b) Q17, 18 respectively: 17. Find constants a, b, c such that the polynomial p(x) = x3-6x2+11x-13 is expressible as X3+aX+b where X=x-c. Hence show that the requation p(x)=0 has only one real root. 18. Factorise...

I still would go to my school (private Eastern Suburbs school) any day over Kings. The fees are similar and I think it's much better. Kings' grounds are quite big though, I used to live across the road from that school and mucked around quite alot with mates in their vegetation land (which was...

What would you know about Gough Whitlam?

Then what did you get?

Yes they would be, which was my point. But having 'a' positive is conventional. IIRC, even to graph it, you can do it concave up or down and get full marks; but I may be wrong.

... Do you guys bother to read? Do you think there's any reason that I quoted minijumbuk ? .. or did I just do it for fun? Geez, people today...

No, there isn't... x²+3x-10=0 and -x²-3x+10=0 are the SAME, you get: x=-5, x=2 and -x=5, -x=-2, which are the SAME. and my working was correct...

Sum of the roots = 2 + (-5) = -3/1=-b/a Product of the roots = 2*-5 = -10/1=c/a Therefore (a, b, c) = (1, -3, -10) Now, a quadratic equation is of form ax2-bx+c=0 Therefore equation is x2+3x-10=0