Quartic Roots
Forth degree equations are almost unsolvable for me. Please help!
Solve the equation 6x^4-11x^3-26x^2+22x+24=0 given that the product of two fo the roots is equal to the product of the other two.
I guess its my mistake, but i left out a part of the q, where it said, find in terms of a and b
So thats where i am stuck, how would you get from (a^2+b^2)/ab = z+y
to getting z=a/b and y=b/a
But how do you measure that? By age, generalising for all children? What if the child is 17.. or just a mature 15 yr old.
What about necrophilia? Or consentual canniablism?
But who actually benefits from making society good? The people are surely not. They are mere slaves to the communist regime, suffering a plain, healthy diet.
But the greater query is not this. It is rather why do we propose such propostrous argument, when no one is truly benefitted? Well, its...
If a and b are roots of the equantion x^2 + mx + n = 0, find the roots of
nx^2 + (2n-m^2)x + n = 0
Let roots of equn nx^2 + (2n-m^2)x + n = 0 be z, y
i know that
zy = 1
and
z+y = (2n-m^2)/n
but what i cant figure out is how to get a and b from z+y