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D
Q16
May I ask as c>0, so 1+4 r^2>0 Or 4 r^2 > -1 How can you deduce that r> 1/2?- drlisir
- Post #145
- Forum: Mathematics
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D
Q16
16(c)I. Solving simultaneously: x^2 +(y-c)^2=r^2 and y=x^2 for the coordinates of the touching points, Hence : y+(y-c)^2=r^2, which is a quadratic equation in y. Buy the touching points are equal in y coordinates, so discriminant of the equation equals to 0. So (1-2c)^2 - 4 (c^2 - r^2 = 0...- drlisir
- Post #143
- Forum: Mathematics
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