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I got a = 3 and b = 11. For the first one, substitute 2 in for x: 216 = 16a + 8b + 60 + 18 + 2 216 = 80 + 16a + 8b 27 = 10 + 2a + b (1) And the next one, -1 for x: 0 = a - b + 8 (2) So through simultaneous equation, Eq (1) + Eq (2) gives 27=18 + 3a a=3 and b=11

3. It makes sense to me now *phew*. 4. I'll do the individual +- cases myself, no worries bout that. Thanks for your help. :)

Would appreciate it if anyone could help me with these sums; I tried doing them and came up with different answers from the ones in the book. So I'm not sure now if I did them wrong, or there are mistakes in the book's answers: (y2 - 6)/y < y |x-3|/(3-x) = x x2 > a2 |x - 3| +...

In the second triangle, where does the extra square come from? :)

Just checking, but are we referring to the same thing? http://apcentral.collegeboard.com/apc/public/courses/syllabi/index.html

Greetings from the equatorial, if not equally sunny, land of Malaysia :wave: In order of most-liked to most despised subject: -Chemistry -Biology -Maths Ext. 1 -Maths -Advanced English -Physics - well, I don't really hate it, but... -IPT (probably due to the teacher more than anything else)...