The question is strangely odd if its a standalone question, there should have been a question before this that leads to this otherwise the "Hence" part of the question is just... odd..
BHHS 2009 Ext 2 Trial Question 6 part c
haha a bit of a strange question that i have no idea how to do..
its just pratically find the limitting value of what i posted underneath =)
The questions a bit long so i'll decide to post up the link instead of typing up the question
http://au.geocities.com/ext2papers/cssa2008.pdf
I'm interested in knowing how you do question 6b ii)
o__o... strange question if you ask me... no idea how you would do it..
fundamentally theres nothing wrong with it i just never did anything like that so i wouldnt be able to remember it... and since i have trials the day after tomorrow i dont think i would be able to do something like that.. =="
haha wow... o_O. i just did it like 5 seconds before i checked up on here after like 45 minutes of trying it but i got it doing it really strangely lol. x__X... haha seems theres lots of quirky methods around... i like the first guys method seems quite genius tho i dont think im gonna be able to...
I cant seem to get this question down and i'm not really sure why ><" tried it for like 30 minutes and I couldn't get it would someone be able to post up a solution?
The polynomial equation x^5 - ax^2 + b = 0 has a multiple root.
Show that 108a^5 = 3125b^3
By that logic... If I really wanted to get a state ranking, I wouldn't shouldn't really goto James Ruse or anything... say theoretically i come 5th at Ruse but I get 100% in the external exams... I might not come first in the state... but then if i went to some crappy school in some crap hole...
(1+sin pi/5 + icos pi/5)^5 + i(1 + sin pi/5 - i cos pi/5) = 0
(sin pi/5 + icos pi/5)^5 + i = 0
(cos(pi/2-pi/5) + isin(pi/2-pi/5))^5 + i
then just de moivres and im done?