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Can someone show the working out to this question for me....for some reason im not getting it right. Kate plans to retire at age 60. At that time, she wants to have enough to invest in a travel account so that she can go on a world trip every four years until she reaches 76, i.e. at ages 64...

using subsitution the answer is wrong, but from what i know, it should work integral (sinx.cosx) =integral (u) let u=sinx, du=cosx dx =1/2u^2 +c =1/2sin^2x +c =1/2[1/2(1-cos2x)] +c =1/4-1/4cos2x +c but then there's also, integral (sinx.cosx) =1/2 integral (sin2x) =1/2.-1/2cos2x...