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yes that is correct. as you can see on that graph, there is one full cycle between -2pi to 0, and another full cycle between 0 to 2pi. that is because the period is 2pi, but they've asked for a graph between -2pi and 2pi, in this case meaning the tan is essentially drawn twice.

btw for q2 it was asking for grad of normal, not tangent.. so the answer is -1/6 1. Well... you can take it as Integrate (cosx) between pi & 0 ... i intregrated to sinx between pi & 0 so sin pi - sin 0 .... well that = 0 ...... :S i donno if that's right. 2. yeah the period is 2pi, so...

I can very vaguely remember doing this but I will give my opinion. With a), by saying the boat is 8ms^-1 due north, then i think we can take that as relative to the Earth. if the current of water is said to be flowing from the west, then that is relative to the earth. Vbe=8 north Vwe=15...

We should at least have a choice between taking English language and English literature like the British system. I am never going to be analysing the poetic techniques when i move forward into a job after school - it is really a stupid system. Or they should make English not compulsorily...

here is how i did it : y = ax^3 + bx^2 - x + 5 y' = 3ax^2 +2bx - 1 y'' = 6ax + 2b pt of infl; .:. 0 = 6a(1) + 2b .:. 0 = 6a + 2b [1] we know a pt on the curve is (1, -2) .:. -2 = a(1)^3 + b(1)^2 - 1 + 5 .:. -2 = a + b -4 .:. -6 = a + b [2] solve simultaneously: -36 = 6a + 6b [3] [3] - [1]...

Ok here is how to find h: 2x + y = 42 .:. y = 42 - 2x we can see that the bottom 24 cm side minus the bits to the left and right is equal to y. (we will call each side "z") .:. 42 - 2x = 24 - 2z .:. 21 - x = 12 - z .:. z = x - 9 now we have the base of the right angled triangle we are gonna...

A relational database is basically two or more tables in one database which have a field that links them together in some way. It allows you to group common data without data redundancy more or less. Here or some basic instructions (it depends what version of access you have): 1. open microsoft...

To put it realistically, i think that this is the best advice you can follow. IPT is possibly the shittest subject that you could ever take. Every time i go to class im either feeling like i want to gouge my eyes out, or im just staring at a wall. Either way, its more productive than IPT will...

My suggestions: i) draw them yourself (this is pretty easy i would think) or ii) have your teacher fired for forcing you to do something so unbelievably irrelevant that you would never possibly be asked in any form in any real external examination. ...Or i probably just mis-interpreted the...

Yes, both are correct.

Yes, A B and D are correct. C, however, is wrong. At the maximum height, vertical velocity is 0, due to the acceleration of gravity downards. However, we know that horizontal velocity remains constant throughout the flight. Therefore, the answer to C is the horizontal velocity, 69.28 ms^-1...