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What school are you at?

This poster: (i) did not read the thread; (ii) did not follow the links provided; (iii) doesn't know what they are talking about; (iv) all of the above.

There are steps missing that would be taught in the class. First question: odd integrand. Second question: let u = 1 - (x-2)^2. If you are super awesome, you could do this without the substitution though - it's not mandatory.

This is a very similar question. It also supplies a second method for doing the question. .

It's pretty easy hat. Take ln of both sides to start with. Call this equation (1). Multiply through by x. Differentiate. Multiply through by y. Rearrange to have dy/dx on one side. Multiply through by x so that the dy/dx side of the equation is as required. Use equation (1)...

The question says: RTP: A = B - C. It is perfectly reasonable to restate the question and say: RTP: A - B = - C These are EQUIVALENT questions or proofs. HOWEVER you wrote the equation: A - B = - C WITHOUT WRITING "RTP:" BEFORE IT and then commenced your working...

If you wrote "RTP:" before your restatement of what you are trying to prove then that would be correct. You did not. Without it, you are technically making a statement that has obvously not yet been proved. In the HSC, you would probably not be penalised for such a mistake. But if your...

i was at the bunnies game so psyched GO BUNNIES finally not such shit fucks got rained on but it was mad GO BUNNIES ZOMG LSOOLZ

This is correct.

Yes, if you're assuming that from eldest to youngest we have: a,b,x,y.

Oh yah you are clearly correct. For some reason when I wrote the answer I thought you had specified that letters could not be used more than once.

I do not. Why do you ask?

My Question: The sum of the ages of the four children of a family is equal to half the age of their father. The difference of the squares of the ages of the oldest and youngest children is equal to the age of the father, which is also equal to twice the sum of the differences of the squares...

everything to do with finding complex roots thanks bye

You are a little behind but not excessively so.

I assumed because usually you type your documents (as you said). Silly me! :(

Both documents are a useful read. But the second pdf is in bad need of typing! (I know you didn't create it).

Shady01, your first line is wrong. If you were to go down the z = x + iy path, using modulus definitions: sqrt(c) + sqrt(d) = 10 You can't just square both sides to get c + d = 100. In fact, the easiest way to do this is to rearrange as sqrt(c) = 10 - sqrt(d) and then square both...

You've got to be joking. You think the HSC Examiners borrowed from the Excel book? THE EXCEL BOOK? Quite possibly the worst textbook on the market? This is a question that appears in every textbook and is taught by every teacher that isn't a complete retard. I'm not going to even bother with...