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You can get the past exam papers from the library web site. Yup that's quite an accurate statement I think. The style of questions will be largely influenced by who your lecturer is and what sorts of questions (s)he likes setting. As far as harder tutorial questions go, it's unlikely that...

[Inside-joke] Well at least you know about reading oracle files. That's gotta count for something. [/Inside-joke]

Heh I'm the Indian guy who just sits in awe of the greater mathematical minds in the class :D

MathWorld's entry on the square root may be of interest.

Hehe yeah I heard about that..but isn't the scaling based on the assignments you get in the SSP?

Cool, I'm in the SSP for maths too! Should be pretty interesting I think. I learnt that the maths SSP is not the same as the maths TSP, so I guess I won't be doing the maths TSP after all (well not this semester anyway).

Is anyone here doing the science Talented Students Program? If so, what are you going to do it in? I think I will be doing it in Maths, and maybe Physics, depending on what kind of stuff it offers. Also, do we have a TSP meeting on Wed??

Don't mind me, I was feeling pedantic :) I haven't done maths in a while either, I had to check on the net that I was right :D

Close, e^{i<FONT FACE="Symbol">p</FONT>} = -1 :p

I attended, but I left during lunch! With my luck all the interesting stuff must've happened as soon as I left..

You can just use the HTML &lt;sup&gt; (and the corresponding &lt;/sup&gt;) tag for superscripts e.g. x&lt;sup&gt;n + 1&lt;/sup&gt; becomes x^{n + 1}, etc. EDIT But forgetting to close the tag can cause things to get messy...

AFAIK, quality assurance is a process that occurs during testing and evaluating. It is where there is a group of people who basically look at the software and its performance in comparison to a set of pre-defined standards..that is, they decide whether or not the software has enough 'quality' to...

The 4U question can be done by writing cos 7x + cos 5x = cos (6x+x) + cos (6x-x) and cos x + cos 3x = cos (2x - x) + cos (2x + x), and then simplifying by using cos (A+B) + cos (A-B) = 2cos A cos B.

Hardest? Q8(b), 1989 (which not a single candidate was able to complete BTW). Simple: 6 * 9 = 42 :D

A similar method is to write 2^x as e^{x ln 2}, then do it normally.

The factorial is defined in terms of Euler's gamma function, which is an integral. The integral is Gamma(n) = int x^(n-1) e^-x over x = 0 to x = inf. and it can be shown that Gamma (n) = (n - 1)!. So put n = 1 and the integral is the integral of e^-x over x = 0 to x = inf. is 1, which...

Okay, tell me if this is right - when you consider $27, that already includes the $2 the waiter pocketed, therefore by adding $27 and $2 you are not finding out the total money, so there is no contradiction. What can be done with the $27 and $2 is subtract them to get $25, the cost of the meal.

AFAIK, the error is when you say root (-1/1) is the same as (root -1) / (root 1). This law of indices does not hold for negative numbers, so you can't split up the square root like that. Similar thing for the second one, (root -1)*(root -1) is not the same as root (-1 * -1).

Actually it was proved in 1994 by Andrew Wiles